Determine if the following statement is true or false. "Parents with the dominant phenotype cannot have offspring with the recessive phenotype." O False, because both parents could be heterozygous. O True, because the dominant gene must be passed down from each parent. O True, because both parents have the dominant allele. False, because one parent could be heterozygous.
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- Question 1 refers to the pedigree chart in Figure 11.2 for a family, some of whose members exhibit the dominant trait, W. Affected individuals are indicated by a dark square or circle. 1) What is the genotype of individual II-5? What are the genotypes of individuals II-2, 3, and 4 and II-6, 7, and 8?Question 6: If individuals IV-4 and IV-5 mate and have a child, what is the probability that the child will have the genetic condition? Assume people mating into the pedigree do not carry the abnormal allele unless information given in the pedigree suggests otherwise. Write the probability as a fraction without any spaces, answers given as a decimal will be marked incorrect. (For example write your answer as 5/72 – note that is NOT the correct answer).Question 3. There are 100 students in a class. Ninety-six did well in the course whereas four blew it totally and received a grade of F. Sorry. In the highly unlikely event that these traits are genetic rather than environmental, if these traits involve dominant and recessive alleles, and if the four (4%) represent the frequency of the homozygous recessive condition, please calculate the following: A) The frequency of the recessive allele. B) The frequency of the dominant allele. C) The frequency of heterozygous individuals. Question 4 Within a population of butterflies, the colour brown (B) is dominant over the colour white (b). And, 40% of all butterflies are white. Given this simple information, which is something that is very likely to be on an exam, calculate the following: A) The percentage of butterflies in the population that are heterozygous. B) The frequency of homozygous dominant individuals. Question 5 A rather large population of organisms have 396 red-sided individuals…
- Question 10. Identify the three ways that a karyotype can be organized.Question: Red color (R) allele is dominant over blue color (r) for carnations (a type of flower). You will cross a heterozygous red carnation with a blue carnation. Show all your work filling out the required parts of the diagram. Then, select the correct statement below. (Picture below) 1. 75% red - 25% blue 75% heterozygous - 25% homozygous 2. 75% red - 25% blue 75% heterozygous - 25% homozygous 3. 50% red - 50% blue 50% heterozygous - 50% homozygous 4. 25% red - 75% blue 25% heterozygous - 75% homozygousQuestion 26 refers to QTL on the cricket autosomes. Forthe sex chromosomes, females crickets are XX and malescrickets are XO, having just one X chromosome but noY chromosome. Can QTL for pulse rate be mapped oncricket X chromosomes? If the song is only sung by malecrickets, can the dominance effects of QTL on the X beestimated?
- QUESTION 1 The figure shown below indicates two Labrador retrievers that are both homozygous recessive for fur color. One dog is brown and the other is yellow due to a. pleiotropy. c incomplete dominance. d. epistasis. QUESTION 3 Which of the following did Gregor Mendel notice in garden peas? a. Some plants always produced offspring with flowers that were the same color as the parent plants’ flowers. b. Garden peas always produce a variety of phenotypes in their offspring, which result from frequent mutations. c. Any individual pea plant carries at least three different alleles for flower color. QUESTION 4 A chestnut-colored (red-colored) horse is mated with a cremello (cream-colored) horse. Over a 10-year period, all of their offspring are palominos (gold-colored). This pattern of inheritance is best explained by a. environmental effects on genes. c. multiple gene effects. d. incomplete…A pea plant with yellow round (Y_R_) seeds is crossed with a second pea plant with green wrinkled (yyrr) seeds. What would the phenotypes of the offspring be if the yellow round pea plant was homozygous for both traits? Question 34 options: All yellow round 1 yellow round : 1 green wrinkled 3 yellow round : 1 green wrinkled 1 yellow round : 3 green wrinkledQuestion 6 Albinism is caused by an autosomal recessive allele that interferes with skin pigmentation in mammals. Two normally pigmented human parents already have an albino boy. They plan to continue to have children until they get a girl. Some or all of this information is important for each of the questions below. a) What is the probability that their next child (currently unborn) will be a girl with albinism? Explain your reasoning. b) What is the probability their first female child will be albino? Explain your reasoning. c) The answer to part (b) is different (and, yes, the answer is different) from the answer to part (a). Explain why. (Hint: it has something to do with the underlined words.)
- QUESTION 2 A male hare with the genotype AaBb is crossed with a female hare with the genotype AABb. Use a Punnet square to determine the genotypes, phenotypes and proportions in the offspring. Show all your working. [17] A = black hair a = yellow hair B = brown eyes b = blue eyesQuestion: Suppose the progeny were crossed. Fill in the Punnett Squares below and answer the following questions. Seed Color Seed Shape R r A a In a pea plant experiment, the allele (R) producing yellow seed color is dominant, and the allele (r) producing green seed color is recessive. A homozygous recessive genotype would produce green seeds. Similarly, the allele (A) producing round seed shape is dominant to the allele (a) that produces wrinkled seed shape. A homozygous recessive genotype would produce wrinkled seeds. Both traits sort independently of each other. Given a pure-breeding cross between a round, green pea plant and a wrinkled yellow plant, complete the rest of the Punnett Squares below, and answer the following questions. R R A A RA Ra Ra raAnswer option for 1: A) independent, B) mutually exclusive, C) mutually inclusive, D) interdependentAnswer options for 2: A) add, B) multiply, C) multiply then add, D) add then divide3 and 4 are fill in the text box.