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Determine if the series converges or diverges. Use any method, and give a reason for your answer. 00 Σ 1 3 k=3√k-4k+ 12 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. The series diverges because the limit found in the nth-Term Test is 00 Ο B. Because Σ ∞0 Σ k=3√k-4k+12 k=3√k O E. 1 1 ∞0 and Σ OC. The series diverges per the Integral Test because ak Since lim = 1, where ak k→∞obk 1 k=3√3 1 √k-4k+12 00 3 √k-4k+12 OD. The series converges because it is a geometric series with r= and bk = Test. OF. The series diverges because it is a p-series with p = converges, the series converges by the Direct Comparison Test. 1 *** dx= , both series have positive terms, and the series 00 1 k=3√√k³ converges, the given series converges by the Limit Comparison

Determine if the series converges or diverges. Use any method, and give a reason for your answer. 00 Σ 1 3 k=3√k-4k+ 12 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. OA. The series diverges because the limit found in the nth-Term Test is 00 Ο B. Because Σ ∞0 Σ k=3√k-4k+12 k=3√k O E. 1 1 ∞0 and Σ OC. The series diverges per the Integral Test because ak Since lim = 1, where ak k→∞obk 1 k=3√3 1 √k-4k+12 00 3 √k-4k+12 OD. The series converges because it is a geometric series with r= and bk = Test. OF. The series diverges because it is a p-series with p = converges, the series converges by the Direct Comparison Test. 1 *** dx= , both series have positive terms, and the series 00 1 k=3√√k³ converges, the given series converges by the Limit Comparison

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Determine if the series converges or diverges. Use any method, and give a reason for your answer. ∞ Σ 1 3 k=3√k - 4k+ 12 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The series diverges because the limit found in the nth-Term Test is ∞ Ο B. Because Σ 1 3 k=3√k - 4k + 12 O E. ∞ Σ k = 3 ak = Since lim = = 1, where ak k→∞ k ∞ OC. The series diverges per the Integral Test because ļ 3 3 1 √K 3 k - ∞ and Σ k = 3 1 O D. The series converges because it is a geometric series with r = - 4k + 12 and bk 1 Test. O F. The series diverges because it is a p-series with p = 3 converges, the series converges by the Direct Comparison Test. = 3 1 1 - 4k + 12 3 " -dx = both series have positive terms, and the series ∞ - 10/2/2 1 3 k=3√k converges, the given series converges by the Limit Comparison
Transcribed Image Text:Determine if the series converges or diverges. Use any method, and give a reason for your answer. ∞ Σ 1 3 k=3√k - 4k+ 12 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The series diverges because the limit found in the nth-Term Test is ∞ Ο B. Because Σ 1 3 k=3√k - 4k + 12 O E. ∞ Σ k = 3 ak = Since lim = = 1, where ak k→∞ k ∞ OC. The series diverges per the Integral Test because ļ 3 3 1 √K 3 k - ∞ and Σ k = 3 1 O D. The series converges because it is a geometric series with r = - 4k + 12 and bk 1 Test. O F. The series diverges because it is a p-series with p = 3 converges, the series converges by the Direct Comparison Test. = 3 1 1 - 4k + 12 3 " -dx = both series have positive terms, and the series ∞ - 10/2/2 1 3 k=3√k converges, the given series converges by the Limit Comparison
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