determine its unit weight. The following data are obtained: Volume of bucket = 9.3 Liters Mass of empty bucket = 9 kg Mass of bucket filled with dry-rodded coarse aggregate: Trial 1 = 30.25 kg Trial 2 = 29.76 kg Trial 3 = 31.12 kg a. Calculate the individual dry-rodded unit weight for each trial and the average dry-rodded unit weight of all trials. b. If the bulk dry specific gravity of the aggregate is 2.65, calculate the percent voids between aggregates particles for each trial and the average percent voids of all trials
Show complete solution.
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:
Volume of bucket = 9.3 Liters
Mass of empty bucket = 9 kg
Mass of bucket filled with dry-rodded coarse aggregate:
Trial 1 = 30.25 kg
Trial 2 = 29.76 kg
Trial 3 = 31.12 kg
a. Calculate the individual dry-rodded unit weight for each trial and the average dry-rodded unit weight of all trials.
b. If the bulk dry specific gravity of the aggregate is 2.65, calculate the percent voids between aggregates particles for each trial and the average percent voids of all trials.
Step by step
Solved in 4 steps with 4 images