Determine the amplitude, period, and phase shift for y- tan( 8+ 30°) and use them to plot the graph of the function. amplitude = does not exist; period = 180°; phase shift = -30° 45 35 3 25 15- 1 05+ 276 6-05+ -1+ -15+ -2 -25 то -180 0-05 90 180 -35 amplitude = does not exist; period = 180°; phase shift = –30° %3D 45 35 3 25 15- 05 -270 -180-90 0s+ -1- -15+ 180 / 270 / 90 -25+ -3- amplitude = does not exist; period = 180°; phase shift = 30° 43 4- 35 + 3 + 25 2 15+ 1- -270 -180 -90 6s+ -1+ -15+ -2+ -25+ 90 180 270 -35· amplitude = ; period = 180°; phase shift = -30°

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.5: Trigonometric Graphs
Problem 5E
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Question
Determine the amplitude, period, and phase shift for y-tan( 6+ 30°) and
use them to plot the graph of the function.
amplitude
= does not exist; period = 180°; phase shift = –30°
05t
-10 -180
6-05
180
amplitude = does not exist; period = 180°; phase shift = -30°
45-
35+
05
-270/ -180/ -90 f0s-
90
180
270
-15-
-2
-25-
-35-
amplitude = does not exist; period = 180°; phase shift = 30°
05
-270 -180
-90 6S
90
180
270,
-15-
amplitude = ; period = 180°; phase shift = -30°
Transcribed Image Text:Determine the amplitude, period, and phase shift for y-tan( 6+ 30°) and use them to plot the graph of the function. amplitude = does not exist; period = 180°; phase shift = –30° 05t -10 -180 6-05 180 amplitude = does not exist; period = 180°; phase shift = -30° 45- 35+ 05 -270/ -180/ -90 f0s- 90 180 270 -15- -2 -25- -35- amplitude = does not exist; period = 180°; phase shift = 30° 05 -270 -180 -90 6S 90 180 270, -15- amplitude = ; period = 180°; phase shift = -30°
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