Determine the effective stress in kPa at a depth of 16 m below the ground level for the following conditions: Water table is 3 m below ground level ; G = 2.68; e = 0.72;average water content of the soil above water table is 8% a.127.5 b.301.6 c.429.1 d.174.1
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- A soil profile is shown in Figure Q3(b)(i). The groundwater level is located on the ground surface. The sand layer is under artesian pressure where the excess pore water pressure is 40 kN/m^2. (i) Calculate the total vertical stress, pore water pressure and effective vertical stress at the base of each layer. (ii)Determine the increment of the effective stress at the base of sand layer if the 1.5m height fill will be imposed on the ground surface. Note that, the density of the fill material is 1750 kg/m^3. (iii) The excavation will be made in the clay layer for the basement construction. Evaluate the stability of the soil from boiling or quick condition. The depth of the excavation is shown in Figure Q3(b)(ii). (iv)Propose the maximum depth of cut that can be made to avoid boiling or quick condition.A granular soil is subjected to a minor principal stress of 200 kN/m2. If the angle of internal friction is 30°, determine the inclination of the plane of failure with respect to the direction of the major principal stress. Show free body diagram. a.30 b.45 c.60 d.37.5Plz give the correct answer. Compute the intensities of active and passive earth pressure at depth of 8 m in dry cohesionless sand with an angle of internal friction of 30 degrees , and unit weight of 18kN / (m ^ 3) What will be the intensities of active and passive pressure if the water level rises to the level? Take the saturated unit weight of sand as 22kN / (m ^ 3) .
- 6. From the given soil profile, the groundwater table is located 2m below the ground level. (See picture below) Compute the horizontal effective stress at point A. (Answer: 53.36 kPa) Compute the lateral effective stress at point A if the lateral earth pressure coefficient at rest is K0=0.50. (Answer: 26.68 kPa) Compute the lateral total stress at point A. (Answer: 56.11 m)A saturated clay layer has a thickness of 10 meters with a water content of 51% and a specific gravity 2.72. Determine the following: 1. Saturated unit weight of the clay * a. 21.46 kN/m³ b. 18.12 kN/m³ c. 16.87 kN/m³ d. 14.95 kN/m³ 2. total stress at depth of 10 meters a. 122.1 kPa b. 151.3 kPa c. 168.7 kPa d. 142.5 kPa 3. Effective stress at depth of 10 meters a. 42.1 kPa b. 70.6 kPa c. 68.7 kPa d. 82.5 kPaEffective Stress in Soil Problem 1. The water table in a certain deposit of soil is at a depth of 2m below the ground surface. The soil consists of clay up to depth of 4m from the ground and below which lies sand. The clay soil is saturated even above the water table: Clay strata: ? = 30%,?? = 2.72 Sandy Strata: ? = 26%, ?? = 2.64 1. Compute the total pressure. 2. Compute the pore water pressure. 3. Compute the effective stress pressure at a depth of 8m below the ground surface
- A soil profile consists of; layer 1, 10m sand layer and layer 2, 3m clay layer. The ground water table is located 4m below ground surface. For sand, γdry=2.00 T/m2 (tons/m2), γsat=2.25 T/m2, and for clay layer, LL=46%, water content=42% and Gs=2.76. A uniform vertical stress, ΔP=20T/m2 is applied at the ground surface. Determine, a) Effective unit weight of clay, b) overburden pressure at the mid point of the clay layer, c) primary consolidation settlementA dense silt layer has the following properties: e =0.406 D10= 10.1 um Capillary constant = 0.209 sq.cm Free ground water level is 8m below the ground surface. 1.) Find the height of capillary rise in the siltin meters. 2) Find the vertical effective stress at 6m depth. Assume ys = 26.51 kn/m3 and the soil above capillary action rise and ground surface is partially saturated at 79%.A soil profile, under surcharge load of 25 kN/m2 at ground level, consists of 6m sand and 3m clay layer. Ground water table is 2m below sand layer. Dry unit weight and saturated unit weight of sand is 15.80kN/m3 and 16.90kN/m3 respectively. Clay layer, Gs=2.67 and saturated unit weight is 18.80 kN/m3. Determine a)Increase in stress at the mid layer of clay b) With dewatering 2m, what is the stress increase at the mid layer of clay c) How much must the water level be lowered to me more effective than the surcharged load?
- The soil in a deposit underlying an area where a level ground surface exists has a unit weight of 22 kN/m3. Determine the principal stresses o1 and oz at a depth of 5 m below the soil surface if the lateral pressure is 0.50 of the vertical pressure. Adjust your answer to ZERO decimal places. 01 = kN/m2, 03 = kN/m2The water table in soil deposit is 2 m below the ground surface. The soil above the water table has dry unit weight of 14.85 kN/m^3. The saturated unit weight of the soil is 20.58 kN/m^3. Determine the total vertical stress, in kPa, at a point 4.8 m below the ground. Determine the total pore water pressure, in kPa, at a point 4.8 m below the ground. Determine the The effective vertical stress, in kPa, at a point 4.8 m below the ground.A dense silt layer has the following properties.void ratio = 0.30eff. Diameter ?10 = 10??capillary constant (c)=0.20 cm²Groundwater level is 8.0m below the ground surface 1. Calculate the height of capillary rise in the silt. 2. Calculate the vertical effective stress in kpa at 5m depth, assume ?? = 26.5 ??/?³and that the soil above the capillary action rise and ground surface is partially saturated at 50%. 3. Calculate the effective vertical stress at 10m depth assuming ?? = 26.5 ??/?³and that the soil above the capillary action rise and ground surface is partially saturated at 50%.