Determine the equivalent torsional spring constant of the system that will be located in the position of point 0. k=1.5N/m. The bar is 2 meters long. (answer in N-m) * k = 2k A kz = k 14

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter10: Virtual Work And Potential Energy
Section: Chapter Questions
Problem 10.57P: Find the stable equilibrium position of the system described in Prob. 10.56 if m = 2.06 kg.
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Determine the equivalent
torsional spring constant of the
system that will be located in
the position of point 0.
k=1.5N/m. The bar is 2 meters
long. (answer in N-m) *
k = 2k
F
A
k2= k
1/4
34
/14
Transcribed Image Text:Determine the equivalent torsional spring constant of the system that will be located in the position of point 0. k=1.5N/m. The bar is 2 meters long. (answer in N-m) * k = 2k F A k2= k 1/4 34 /14
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