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Determine the forces in members DE and DL. The forces are positive if in tension, negative if in compression. 2.2 m, 2.2 m, 2.2 m 2.2 m D. E 1.2 m 0.6 m 2.4 m C 2.4 m 5.3 kN B. 2.4 m Part 1 If we cut through DE, EL, and LK, we can isolate the section to the right of the cut. This section does not have any external reactions, so there is no need to solve for the reactions. The free-body diagram of this section is shown. All members of the truss are assumed to be in tension. E DE G EL K KL 5.3 kN Solve for the force in DE. You can do this with one carefully chosen equation. Answer: DE = i kN

Determine the forces in members DE and DL. The forces are positive if in tension, negative if in compression. 2.2 m, 2.2 m, 2.2 m 2.2 m D. E 1.2 m 0.6 m 2.4 m C 2.4 m 5.3 kN B. 2.4 m Part 1 If we cut through DE, EL, and LK, we can isolate the section to the right of the cut. This section does not have any external reactions, so there is no need to solve for the reactions. The free-body diagram of this section is shown. All members of the truss are assumed to be in tension. E DE G EL K KL 5.3 kN Solve for the force in DE. You can do this with one carefully chosen equation. Answer: DE = i kN

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Determine the forces in members DE and DL. The forces are positive if in tension, negative if in compression. 2.2 m 2.2 m 2.2 m 2.2 m D. E 1.2 m 0.6 m 2.4 m C 2.4 m 5.3 kN 2.4 m Part 1 If we cut through DE, EL, and LK, we can isolate the section to the right of the cut. This section does not have any external reactions, so there is no need to solve for the reactions. The free-body diagram of this section is shown. All members of the truss are assumed to be in tension. E DE G EL K KL 5.3 kN Solve for the force in DE. You can do this with one carefully chosen equation. Answer: DE = i kN
Transcribed Image Text:Determine the forces in members DE and DL. The forces are positive if in tension, negative if in compression. 2.2 m 2.2 m 2.2 m 2.2 m D. E 1.2 m 0.6 m 2.4 m C 2.4 m 5.3 kN 2.4 m Part 1 If we cut through DE, EL, and LK, we can isolate the section to the right of the cut. This section does not have any external reactions, so there is no need to solve for the reactions. The free-body diagram of this section is shown. All members of the truss are assumed to be in tension. E DE G EL K KL 5.3 kN Solve for the force in DE. You can do this with one carefully chosen equation. Answer: DE = i kN
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