Determine the forces on member ABC, presenting your answers as shown. Use F as the last two numbers of your university ID in KN. (if last two numbers are 00 then use F as 10 KN) -(5) F E G D A B - 1m -- 1 m 2 m 1 m

Q: hi P' h2 10 m h3 Q1 15 m Q2 Q3 1 2 3 f 0.02 0.02 0.254 0.02 D 0.406 0.203 5000m 3000m 3500m Q Q2…

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A: Hello dear this is the solution of your problem The answer is found to be K=-3 For explanation…

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A: Example 1 Given  Deflection of beam , Y=w24Ei-X4+2LX3-L3X At X=0 Y=w24Ei-04+2L03-L3×0Y=w24Ei0Y=0 At…

Q: and moment Q. Replace about A 44. force sycen by force at A 200 150 250 350 1. ost

A: To find resultant and moment about A

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Q: Problem 827 See Figure P-827. 150 Ib/ft, 400 Ib 300 Ib 50 Ib/ft 3 ft 5t 4 ft MATHalino.com 12 ft 12…

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Q: 1. Using DIM, solve for: P = 108kN a. Ymu (mm) b. A (rad) Use E = 200 GPa. 165 kN A 1m B 2m 1m CD 2m…

A: Given, E=200Gpa=200 kN/mm2         P=108kN We need to apply Double Integration Method to find out…

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Q: Complete the table by providing the appropriate values. Loading 6Aā /L 6Ab /L 30, kN 4m 6m 10 m 5…

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Q: 31.91*10^6) R=95%, So =0.3, Cd 1.0 J = 3.2, k 130, Ec = 5*10 lb/in.2 Sic =650 lb/in^2, Pt -2.5 Pi…

A: According to AASHTO Design , Reliability, R=95%Ovrall standard deviation, So=0.3Coefficient of…

Q: A1= 200 mm A2= 100 mm water 2 б ст 6 cm S.G.= 0.9 Q3) FIND Q in m3/day

A: Dia of point 1 = 200 mm.... Area A1 = π42002 = 31412 mm2 =  31.412 X10-3 m2 dia of point 2 = 100mm..…

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A: given data diameter of shaft  d=35mmJ=π×d464J=π×35464=73624.41mm4

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Q: y 58KN 300 300 400 20KN 400 33KN

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Q: Using DIM, solve for: a. Ymax (mm) b. A (rad) Use E = 200 GPa. 90 kN/m 165 kN P A 1m 2m 1m 2m 1m 2m…

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Q: An 18. Viscosity of a fluid with specific gravity 1.3 is measured to be 0.0034 Ns/m2. Its kinematic…

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Q: Using DIM, solve for: a. Ymax (mm) b. A (rad) Use E = 200 GPa. 90 167 kN kN/m 165 kN P 120 kN.m L…

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Q: EXERCISE 8. Calculate the vector a x b when a = 2i + j - k and b = 3i – 6j + 2k

A: a=2i+j-k b=3i-6j+2k

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Q: QL-In the figure given below calculate the of (H) for the given data: f1= di= L1= F2= D2= L2= QIL/s)…

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Q: prces F so zero. 150 N -F 125 mm 30 30 130° 150 N 125mm 100mm 45 30 450 100mm F is not on its line…

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Q: H,-0.25 PROBLEM 8.9 A-0.20 Considering only values of e less than 90°, determine the smallest value…

A: Given,

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A: Given:- Pipeline with a reservoir, pump and a pressure measuring gauge having a pressure of -88.29…

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A: given ydy-xdx=0 integrating both sides we have

Q: y F2 = 500 N F1= 600 N 3 35° 4 0.1 m F0.2 m 0.3 m F3= 800 N B 0.4 m as serle

A: Free Body Diagram of the given problem:

Q: Table 1. (For Groups 1 and 8) Computed Values, N Percent Experimental, Values, N Trials Error…

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Q: 3- Use Euler Method to find value of when У(16) (x2 + y?)dx = (x + y)dy, use h = 0.2 Y(1) = 0 for…

A: For finding the numerical solution of first order differentials equations with initial data we go…

Q: IK 1K 60° 60° 60° 60 60 60° G. 10 10' 10 Solve for member AC.

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Q: (FR), (MR)B, F, F2 F3 dz B B 'p- (FR), dz *F4 da C C Equivalent System Original System

A: Consider the following diagram:

Q: c. 7x – 3y = 23 2x + 4y = -8

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Q: Which of the following equations is variable separable? O a. (3x² – y²)dæ – 2xydy = 0 O b. (x² +…

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Properties of materials

A property of a material describes its characteristics and distinguishes it from the others. The material properties are described it in terms of its hardness, color, appearances, and so on. The material properties generally depend on the type of material, or whether it is a metal or an alloy. There are different kinds of material properties such as mechanical properties, thermal properties, physical properties, and chemical properties. Chemical properties describe the material in terms of a chemical change. The mechanical properties come into existence when the material is acted upon by an external load. Thermal properties are associated with the temperature of the material and specific heat.