Determine the INSTRUCTION PE, CONTENT/RESULT of the destination after the execution (if not applicable, NA), the MACHINE CODE, and ADDRESS RANGE when saved in the cS of the given instruction. It will be saved continuously and part of a single program. Instruction type is in SMALL letters. For the machine code, binary is used for the opcode up to the mod reg/RM field but hexadecimal for the displacement and immediate value. Use single space in between bytes. For Address range, registers, and physical memory, use CAPITAL letters. For displacement and immediate values, use CAPITAL letters. Example Answer: Instruction type: data transfer Content of the Destination: AX=12FE (if register) : if memory (lower address first): 12FE0=34,12FE1=12,12FE2=34,12FE3=56 Machine Code: 1001010 10100101 ED FE Address Range: 13ABC-13ABF GIVEN: registers.JPG DS = ADEOH DI = 8557H AX = 9267H| DX = 6081H CS = BDEAH SI = 57B7H SS = 8998H %3D %3D BX = 7236H| IP = 9DCAH CX = CAFEH %3D ВР - ВАЕН %3D %3D 1.JPG .. ADC AX, DEEFH INSTRUCTION TYPE: Blank 1 CONTENT OF THE DESTINATION: Blank 2 MACHINE CODE: Blank 3 ADDRESS RANGE: Blank 4
Determine the INSTRUCTION PE, CONTENT/RESULT of the destination after the execution (if not applicable, NA), the MACHINE CODE, and ADDRESS RANGE when saved in the cS of the given instruction. It will be saved continuously and part of a single program. Instruction type is in SMALL letters. For the machine code, binary is used for the opcode up to the mod reg/RM field but hexadecimal for the displacement and immediate value. Use single space in between bytes. For Address range, registers, and physical memory, use CAPITAL letters. For displacement and immediate values, use CAPITAL letters. Example Answer: Instruction type: data transfer Content of the Destination: AX=12FE (if register) : if memory (lower address first): 12FE0=34,12FE1=12,12FE2=34,12FE3=56 Machine Code: 1001010 10100101 ED FE Address Range: 13ABC-13ABF GIVEN: registers.JPG DS = ADEOH DI = 8557H AX = 9267H| DX = 6081H CS = BDEAH SI = 57B7H SS = 8998H %3D %3D BX = 7236H| IP = 9DCAH CX = CAFEH %3D ВР - ВАЕН %3D %3D 1.JPG .. ADC AX, DEEFH INSTRUCTION TYPE: Blank 1 CONTENT OF THE DESTINATION: Blank 2 MACHINE CODE: Blank 3 ADDRESS RANGE: Blank 4
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Transcribed Image Text:Determine the INSTRUCTION TYPE, CONTENT/RESULT of the destination after the execution (if not applicable, NA), the MACHINE
CODE, and ADDRESS RANGE when saved in the cs of the given instruction. It will be saved continuously and part of a single
program. Instruction type is in SMALL letters. For the machine code, binary is used for the opcode up to the mod reg/RM field but
hexadecimal for the displacement and immediate value. Use single space in between bytes. For Address range, registers, and
physical memory, use CAPITAL letters. For displacement and immediate values, use CAPITAL letters.
Example Answer:
Instruction type: data transfer
Content of the Destination: AX=12FE (if register) :
if memory (lower address first): 12FE0=34,12FE1=12,12FE2=34,12FE3=56
Machine Code: 1001010 10100101 ED FE
Address Range: 13ABC-13ABF
GIVEN:
registers.JPG
...
DS = ADEOH DI = 8557H AX = 9267H DX = 6081H
%3D
CS = BDEAH SI = 57B7H
SS = 8998H
ВP 3 ВАЕН
BX = 7236H IP = 9DCAH
%3D
%3D
СХ 3 САFЕН
%3D
1.JPG
...
ADC AX, DEEFH
INSTRUCTION TYPE: Blank 1
CONTENT OF THE DESTINATION: Blank 2
MACHINE CODE: Blank 3
ADDRESS RANGE: Blank 4
Blank 1
Add your answer
Blank 2
Add your answer
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