Determine the location (x, y) of the centroid of the area. 2 in. 2 in. 4 in. C 4 in. y T 2in + cin 2inuin C A I 2 in. PS: Hints are given in lecture notes on Canvas. ート X 2in A = 2(2+4) = 12 in 2 Area: L.W. = A = B = 2(2+4)= 12 in 2 - C = 214) = 8 in 2 B tx + り Segment A (in²) x (in) 5 (in) x. A lin³) 5.A (in³) 2/2+4) (2+4)/2 A 3(12) 12 3 36 B 2/2+4) (2+4)/2 3(12) 12 3 36 C 2(u) 2/2 1(8) 8 1 8 Σ 32 80 Σ x= 2 (x. Area) = 202 Z Aren 5 = Σ (5. Area) 80 32 = 2.5 Area 32