2.0 ft 2.0 ftDetermine the magnitude of Pfor whichslipping impends, provided h is within therange where it does not cause tipping.a 270 lbb 135 lbc 540 lbd 315 lbIf the magnitude of Pis 250 Ib determineheight ha 4.44 ftwhich tipping impends.b 2.40 ftW = 600 lbc 3.00 ftd 4.80 ftHs = 0.45

A) For slipping to impends- P=Ff=μwFf=0.45×600P=Ff=270 lbTherefore the magnitude ofP=270 lb Hence…

Determine the magnitude of Pfor which slipping impends, provided h is within the range where it does not cause tipping. а 270 1b c 540 lb b 135 lb d 315 lb If the magnitude of Pis 250 lb determine height h for which tipping impends. а 4.44 ft с 3.00 ft b 2.40 ft W = 600 lb d 4.80 ft IP

Determine the magnitude of Pfor which slipping impends, provided h is within the range where it does not cause tipping. а 270 1b c 540 lb b 135 lb d 315 lb If the magnitude of Pis 250 lb determine height h for which tipping impends. а 4.44 ft с 3.00 ft b 2.40 ft W = 600 lb d 4.80 ft IP

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.

Question

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2.0 ft 2.0 ft
Determine the magnitude of Pfor which
slipping impends, provided h is within the
range where it does not cause tipping.
a 270 lb
b 135 lb
c 540 lb
d 315 lb
If the magnitude of Pis 250 Ib determine
height h
a 4.44 ft
which tipping impends.
b 2.40 ft
W = 600 lb
c 3.00 ft
d 4.80 ft
Hs = 0.45

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