Problem 813 Determine the moment over the support R₂ of the beam shown in Fig. P-813.
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- Compute the value of EI5 at the right end of the overhanging beam. 360 1b 120 Ib/ft |~—l°ft—-|-—6fl—> FIG. P6.43Determine the reactions at the supports and draw the bending moment diagram for the following structures. (Ans : θB =16.388/EI, θC =-2.444/EI, Δ=82.819/EI, Ax= - 11.555kN, Ay=17.028kN, MAB=-31.443kNm, Dx=-14.445kN, Dy=30.972kN, MDC=-30.379kNm)Determine the deflection at midspan of the structure Group of answer choices (-5wL^4)/384EI (5wL^4)/384EI (wL^3)/24EI (-wL^3)/24EI
- A 300 mm x 300 mm concrete column which is pin connected at both ends has an unsupported length of 4.6 meters. The column is carry a total factored axial load Pu = 300 kN and a lateral concentrated load of 90 kN acting at the mid-height of the column. Assume fc’ = 21 MPa and Bdns = 0.15. Compute the total moment including the secondary moment due to lateral deflection.a. 75.852 kN.m. c. 124.614 kN.m.b. 635.785 kN.m. d. 90.872 kN.mDetermine the reactions at the supports and draw the bending moment diagram for the following structure if there are support settlements of 8mm, 5mm and 2mm at A, B and C respectively.Given E=200GPa, I=107mm4 .(Ans : θB =-0.0008344, θC =-0.001208, Ay=12.149kN, MAB=-8.872kNm, By=23.258kN, Cy=12.593kN )A W10 × 60 A992 steel column is 16 ft tall with translation and rotation fixed at both ends of thecolumn and for both axes. The column supports a concentric axial dead load of 13 kips and a concentricaxial live load of 39 kips. There is no moment about the y-axis. Take the lateral-torsional bucklingmodification factor as Cb = 1.0. Which of the following is most nearly the maximum moment that canbe placed on the x-axis? (LRFD options are in parentheses.) Choose the correct answer. (A) 133 ft-kips (220 ft-kips)(B) 142 ft-kips (237 ft-kips)(C) 150 ft-kips (257 ft-kips)(D) 166 ft-kips (280 ft-kips)
- Determine the reactions at the supports and draw the bending moment diagram for the following structures if there are a support movement of A to left by 10mm and a support settlement at D by 12mm. Given E=200GPa, I=107mm4 . (Ans : Ax=-0.789kN, Ay=8.431kN, Dx=-15.211kN, Dy=21.7569kN, MD=33.378kNm↺)Determine the reactions at the supports for the following structures by using flexibility method. if there are a support movement of A to left by 10mm and a support settlement at D by 12mm. Given E=200GPa, I=10^7mm4 . Verify the results the RISA-2D.(Ans : Ax=-0.789kN, Ay=8.431kN, Dx=-15.211kN, Dy=21.7569kN, MD=33.378kNm↺)Draw Influence Line -BeamFor the beam shown in Figs:• Draw influence line for RB, Mk and Vk• Determine the value of M and V at section n by using influence linedue to shown loading. l=4m , W=11kN/m , F=21kN , M=9kN.m .
- A continuous beam is supported by a spring at D with spring constant of 40kN/m as shown. Determine the reactions at the supports A and B and the spring force and draw the bending moment diagram. Given E=200GPa, I=4×107mm4 . (Hint : take the spring force as unknown). (Ans : Ay=-9.495kN, By=24.848kN, Dy=4.646kN)A tapered cantilever beam AB supports a concentratedload P at the free end (see figure). The crosssections of the beam are rectangular with constantwidth b, depth dA at support A, and depth dB = 3dA/2 at the support. Thus, the depth d and moment of inertiaI at distance x from the free end are, respectively, d = (dA/2L)(2L+x) I=(bd3/12) =(bd3A/96L3)(2L+x)3 = (IA/8L3)(2L+x)3in which IA is the moment of inertia at end A of thebeam.Determine the equation of the deflection curveand the deflection δA at the free end of the beam dueto the load P.Find force in all membars for the truss shown ,EA=100000 kn,membar AB and BE rise in temperature 40 c ,alpha=12×10^-6..membar CD error to short (1cm)..support E with settlement vertically 1cm