Determine the Norton Equivalent Current Source at terminals a- b. 8 µF 170 cos(1000 t) V 10 i 10 mH O A. 3.74 cos(1000 t+ 90°) Amps O B. 14.96 cos(1000 t+ 90°) Amps OC.9.35 cos(1000 t + 90°) Amps O D. 18.70 cos(1000 t+ 90°) Amps O E. 7.48 cos(1000 t+90°) Amps

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Determine the Norton Equivalent Current Source at terminals a- b.
8 µF
Do
in
170 cos(1000 t) V
10 i
10 mH
O A. 3.74 cos(1000 t+ 90°) Amps
O B. 14.96 cos(1000 t + 90°) Amps
OC.9.35 cos(1000 t + 90°) Amps
O D. 18.70 cos(1000 t+ 90°) Amps
O E. 7.48 cos(1000 t+ 90°) Amps
Transcribed Image Text:Determine the Norton Equivalent Current Source at terminals a- b. 8 µF Do in 170 cos(1000 t) V 10 i 10 mH O A. 3.74 cos(1000 t+ 90°) Amps O B. 14.96 cos(1000 t + 90°) Amps OC.9.35 cos(1000 t + 90°) Amps O D. 18.70 cos(1000 t+ 90°) Amps O E. 7.48 cos(1000 t+ 90°) Amps
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