Determine the plastic moment strength (kN-m) of a C15x50, A36 steel, about the minor axis d = 381 mm bf = 94.39 mm tw = 18.19 mm tf = 16.51 mm
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- 1. An unsymmetrical flexural member consists of a 70 × 600 top flange, a 70 x 400 bottom flange, and a 12 × 180 web. a, Determine the Section Modulus. b. Determine the distance from the bottom of the shape to the horizontal plastic neutral axis. c. If A572 Grade 50 steel is used, what is the plastic moment MPy for the horizontal plastic neutral axis?1. An unsymmetrical flexural member consists of a 70 × 600 topflange, a 70 x 400 bottom flange, and a 12 × 180 web.a, Determine the Section Modulus.b. Determine the distance from the top of the shape to the horizontalplastic neutral axis.c. If A572 Grade 50 steel is used, what is the plastic moment MPy forthe horizontal plastic neutral axis?1. An unsymmetrical flexural member consists of a 70 × 600 top flange, a 70 x 400 bottom flange, and a 12 × 180 web. a, Determine the Section Modulus. b. Determine the distance from the bottom of the shape to the horizontal plastic neutral axis. ( Take note: Bottom Distance i need, not the top distance) c. If A572 Grade 50 steel is used, what is the plastic moment MPy for the horizontal plastic neutral axis?
- Read the question carefully and give me right solution according to the question. A W12x79 of A573 Grade 60 (Fy=415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at the bottom, and has additional support in the weak direction at mid-height. Properties of the section are as follows: A = 14,500 mm^2 Ix = 258.6 x 10^6 mm^4 Iy = 84.375 x 10^6 mm^4 Calculate the effective slenderness ratio with respect to strong axis buckling using theoretical value of k.Is the beam shown below adequate for moment stresses? Use LRFD. Take the elastic section modulus as 123.0 in3, Steel yield stress as 59.72 ksi, and use wuL2/8 to calculate the required moment strength.An unsymmetrical flexural member consists ofa 3 x 30 in. top flange, a 3 x 20 in. bottom flange, and a 60 * 2 in web A. Determine the distance from the top ofthe shape to the horizontal plastic neutral axis. B. If A572 Grade 50 steel is used, what is the plastic moment Mp for the horizontal plastic neutral axis?
- Determine the shear strength for a built-up I shape made up of A709 Gr HPS 70W steel. Flanges: PL 18”x 1.5” Web: PL 36”x 5/8” Unstiffened: Verify, using appropriate Chapter E design provisions, the tabularized (Table 4-7) buckling capacity of a WT6X20 for both the x- and y-axes at (KL)x = (KL)y = (KL)z = 10 ft. Assume A992 steel.A W420x85 steel beam is fully restrained with a uniformly distributed live load of 25 kN/m. The beam has a span of 10m. Use A36 steel. Properties of W40 x 85 A = 10839 mm2 bf = 180 mm tf = 18 mm tw = 11 mm Ix = 310 x 106 mm4 d = 420 mm (Note: Since this is a built-up section, for checking of web slenderness, use h = d - 2tf) 1) Calculate the design shear strength of the section. Check if the section is adequate in shear. USE LRFD and U = 1.2D + 1.6L. 2) Is the maximum deflection at the midspan of the beam due to live load adequate? 3) Calculate the maximum uniform live load that can be carried by the beam.
- Problem 1. A W30 x 116 beams has the top flange restrained against lateral displacement and rotation and has an unstiffened web. A point load is applied to the top flange at 2m. From the left support. The beam spans 12 m. Use A36 steel with yield strength of Fy = 248 Mpa. b. Compute the maximum value of point load that may be applied without web crippling occurring. d = 762 mm; K = 41.28 mm; bf = 266.7 mm; tf = 21.59 mm; tw = 14.33 mmProblem 1. A W30 x 116 beam has the top flange restrained against lateral displacement and rotation and has an unstiffened web. A point load is applied to the top flange at 2m. From the left support. The beam spans 12 m. Use A36 steel with yield strength of Fy = 248 Mpa. a. Compute the maximum value of point loadthat may be applied without web yieldingoccurring. Properties of W30 x 116d = 762 mmK = 41.28 mmbf = 266.7 mmtf = 21.59 mmtw = 14.33 mmAn aluminum strut 2.00m long has a rectangular section 50mm by 30mm. A bolt through each end secures the strut so that it acts as a hinged column about an axis perpendicular to the 50 mm dimension and as a fixed ended column about an axis perpendicular to the 30mm dimension. Determine the safe central load using a factor of safety of 2.5 and E= 70 Gpa.