Please answer in complete solution and draw an fbd.Note: Please use the second picture as guide for the formulas. Thanks wa (3a 2. 8aL+6L3212L²14PL8Pab²L²Mb(b-2a)L²wyLMLLPLLLLbFixed End Moment Formulas12WW[28wa (a²+ 41².4aL)8L2wa ³ (4L-3a)121²Pa²bMa(2b-a)L12:10 33 PL16Pab(L+b)22²3a 1.5aHO1202-a-LMKLLLLLb18W2HAWMABdeflection -0₂-²curve -L-PhumcordEl is constantpositive sign conventionFig. 11-2, Structural Analysis,R.C.Hibbeler 8th edMAB = 2E20A + 0B - 3+ FEM ABMBA= -2E20B + 0A-33A(FEM) AB-3+ FEM BASign convention: All clockwise internal moments and end rotation are positive.MBAFor end span with far end pinned or roller supportPmini2EILWBFig.11-Sb, Structural Analysis, R.C.Hibbeler, 8th ed3EIMN=[N+ FEMNGeneral FormMNEF= [20N+0F-34+ FEMNF Determine the reactions of the given beam using slope deflection method. P₁ = 25 KN, P₂ = 25 KN, and w = 35 kN/mP₁P₂WI put2mCRA=RD =MD=2mNumerical answer in 4 decimal places and positive values only:RE=BkN (Downward)kN (Upward)21kN-mKN (Upward)4mDI8m

Given:Required:Reactions of the beam

Determine the reactions of the given beam using slope deflection method. P₁ = 25 kN, P₂ = 25 kN, and w = 35 kN/m P₁ P2 H 2m B 2m RA RD= Numerical answer in 4 decimal places and positive values only: kN (Downward) Mp= RE= kN (Upward) kN-m с kN (Upward) 21 4m ↓↓ W 8m I

Determine the reactions of the given beam using slope deflection method. P₁ = 25 kN, P₂ = 25 kN, and w = 35 kN/m P₁ P2 H 2m B 2m RA RD= Numerical answer in 4 decimal places and positive values only: kN (Downward) Mp= RE= kN (Upward) kN-m с kN (Upward) 21 4m ↓↓ W 8m I

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Please answer in complete solution and draw an fbd.
Note: Please use the second picture as guide for the formulas. Thanks

wa (3a 2. 8aL+6L3
2
12L²
14
PL
8
Pab²
L²
Mb(b-2a)
L²
wy
L
M
L
L
P
L
L
L
L
b
Fixed End Moment Formulas
12
W
W[2
8
wa (a²+ 41².4aL)
8L2
wa ³ (4L-3a)
121²
Pa²b
Ma(2b-a)
L
12:
10 3
3 PL
16
Pab(L+b)
22²
3a 1.5a
HO
120
2
-a-
L
MK
L
L
L
L
L
b
18
W2
HA
W
MAB
deflection -0₂-²
curve -L-
P
hum
cord
El is constant
positive sign convention
Fig. 11-2, Structural Analysis,R.C.Hibbeler 8th ed
MAB = 2E20A + 0B - 3+ FEM AB
MBA= -2E20B + 0A-33
A
(FEM) AB
-3+ FEM BA
Sign convention: All clockwise internal moments and end rotation are positive.
MBA
For end span with far end pinned or roller support
P
mini
2EI
L
W
B
Fig.11-Sb, Structural Analysis, R.C.Hibbeler, 8th ed
3EI
MN=[N+ FEMN
General Form
MNEF= [20N+0F-34+ FEMNF

Determine the reactions of the given beam using slope deflection method. P₁ = 25 KN, P₂ = 25 KN, and w = 35 kN/m
P₁
P₂
W
I put
2m
C
RA=
RD =
MD=
2m
Numerical answer in 4 decimal places and positive values only:
RE=
B
kN (Downward)
kN (Upward)
21
kN-m
KN (Upward)
4m
D
I
8m

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