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Determine the subtransient fault current in per-unit and in kA, as well as the per-unit line-to-ground voltages at the fault bus for a bolted single line-to-ground fault at the fault bus selected in Problem 9.2. Repeat Problem 9.14 for a bolted double line-to-ground fault.

Determine the subtransient fault current in per-unit and in kA, as well as the per-unit line-to-ground voltages at the fault bus for a bolted single line-to-ground fault at the fault bus selected in Problem 9.2. Repeat Problem 9.14 for a bolted double line-to-ground fault.

Power System Analysis and Design (MindTap Course List)
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter9: Unsymmetrical Faults
Section: Chapter Questions
Problem 9.14P
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Only need answers for the second question(9.17) at bus 1.

9.14 Determine the subtransient fault current in per-unit and in kA, as well as the per-unit line-to-ground voltages at the fault bus for a bolted single line-to-ground fault at the fault bus selected in Problem 9.2. 9.17 Repeat Problem 9.14 for a bolted double line-to-ground fault.
Transcribed Image Text:9.14 Determine the subtransient fault current in per-unit and in kA, as well as the per-unit line-to-ground voltages at the fault bus for a bolted single line-to-ground fault at the fault bus selected in Problem 9.2. 9.17 Repeat Problem 9.14 for a bolted double line-to-ground fault.
The single-line diagram of a three-phase power system is shown in Figure 9.17. Equipment ratings are given as follows: Synchronous generators: G1 1000 MVA 15 kV 1000 MVA G2 G3 500 MVA 15 kV 13.8 kV 13.8 kV G4 750 MVA Transformers: T1 1000 MVA T2 1000 MVA T3 500 MVA T4 750 MVA SYMMETRICAL FAULTS Line 1-2 Transmission lines: 1-2 765 kV 1-3 765 kV 2-3 765 kV 15 kV A/765 kV Y 15 kV A/765 kV Y 15 kV Y/765 kV Y 15 kV Y/765 kV Y ₁² ◄ Line 1-3 2 2 X = X₂ = 0.18, Xo = 0.07 per unit X = X₂ = 0.20, Xo = 0.10 per unit X = X₂ = 0.15, Xo = 0.05 per unit X = 0.30, X₂ = 0.40, Xo = 0.10 per unit T₂ Line 2-3 X₁ = 50 £2, Xo = 150 2 X₁ = 40 92, Xo = 100 2 X₁ = 40 92, Xo = 100 2 X = 0.10 per unit X = 0.10 per unit X = 0.12 per unit X = 0.11 per unit 3 T3 T₁ 4 youthy
Transcribed Image Text:The single-line diagram of a three-phase power system is shown in Figure 9.17. Equipment ratings are given as follows: Synchronous generators: G1 1000 MVA 15 kV 1000 MVA G2 G3 500 MVA 15 kV 13.8 kV 13.8 kV G4 750 MVA Transformers: T1 1000 MVA T2 1000 MVA T3 500 MVA T4 750 MVA SYMMETRICAL FAULTS Line 1-2 Transmission lines: 1-2 765 kV 1-3 765 kV 2-3 765 kV 15 kV A/765 kV Y 15 kV A/765 kV Y 15 kV Y/765 kV Y 15 kV Y/765 kV Y ₁² ◄ Line 1-3 2 2 X = X₂ = 0.18, Xo = 0.07 per unit X = X₂ = 0.20, Xo = 0.10 per unit X = X₂ = 0.15, Xo = 0.05 per unit X = 0.30, X₂ = 0.40, Xo = 0.10 per unit T₂ Line 2-3 X₁ = 50 £2, Xo = 150 2 X₁ = 40 92, Xo = 100 2 X₁ = 40 92, Xo = 100 2 X = 0.10 per unit X = 0.10 per unit X = 0.12 per unit X = 0.11 per unit 3 T3 T₁ 4 youthy
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ISBN:
9781305632134
Author:
J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:
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