Determine the value of 6>0 for which lim (3x² – 1) = 47 x+ 4 A 6 = max{ – 4-16 -5, - 4 +/16+ 3 들) 3 6 = min{ – 4 +/16 - - 4 -/16+ 6 = max{4 -16 - 4 +16- 6 = min{4 -16-, -4 +/16+ 3 들) D } B,

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 15E
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Determine the value of 6>0 for which lim (3x² – 1) = 47
X+ 4
O 6- max{ -4-16-.-4+/16+)
- 4+16+
0-min(-4+/16-등-4-y16.등)
B
-4-16+
6 = max{4–/16 –
4+16+
D
6 = min{4 -16 –
- 4+16+}
3
3
Transcribed Image Text:Determine the value of 6>0 for which lim (3x² – 1) = 47 X+ 4 O 6- max{ -4-16-.-4+/16+) - 4+16+ 0-min(-4+/16-등-4-y16.등) B -4-16+ 6 = max{4–/16 – 4+16+ D 6 = min{4 -16 – - 4+16+} 3 3
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