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Determine whether or not the table is a valid probability distribution of a discrete random variable. Explain fully. a. 4 -2 P(X=x) 0.3 0.5 | 0.2 0.1 The total of the probabilities must equal to 0- 1. Adding (0.3) + (0.5) + (0.2) + (0.1) = 1.1. Which makes this table not a valid probability distribution because 1.1 does not meet to 1. b. 0.5 0.25 0.2 | 0.05 P(X=x) -0.4|| 0.4 | 0.5 0.5 Adding (-0.4) + (0.4) + (0.5) + (0.5) = 1.| C. -2 -1 2 P(X=x) | 0.16 | 0.14 | 0.11 | 0.27 | 0.22

Determine whether or not the table is a valid probability distribution of a discrete random variable. Explain fully. a. 4 -2 P(X=x) 0.3 0.5 | 0.2 0.1 The total of the probabilities must equal to 0- 1. Adding (0.3) + (0.5) + (0.2) + (0.1) = 1.1. Which makes this table not a valid probability distribution because 1.1 does not meet to 1. b. 0.5 0.25 0.2 | 0.05 P(X=x) -0.4|| 0.4 | 0.5 0.5 Adding (-0.4) + (0.4) + (0.5) + (0.5) = 1.| C. -2 -1 2 P(X=x) | 0.16 | 0.14 | 0.11 | 0.27 | 0.22

Algebra and Trigonometry (MindTap Course List)
Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter14: Counting And Probability
Section14.3: Binomial Probability
Problem 33E
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Determine whether or not the table is a valid probability distribution of a discrete random variable. Explain fully. a. -2 P(X=x) 0.3 0.5 0.2 0.1 The total of the probabilities must equal to 0- 1. Adding (0.3) + (0.5) + (0.2) + (0.1) = 1.1. Which makes this table not a valid probability distribution because 1.1 does not meet to 1. b. 0.5 0.25 0.2 0.05 P(X=x) -0.4| 0.4 0.5 0.5 Adding (-0.4) + (0.4) + (0.5) + (0.5) = 1.| C. -2 -1 1. P(X=x) | 0.16 0.14 | 0.11 | 0.27 | 0.22
Transcribed Image Text:Determine whether or not the table is a valid probability distribution of a discrete random variable. Explain fully. a. -2 P(X=x) 0.3 0.5 0.2 0.1 The total of the probabilities must equal to 0- 1. Adding (0.3) + (0.5) + (0.2) + (0.1) = 1.1. Which makes this table not a valid probability distribution because 1.1 does not meet to 1. b. 0.5 0.25 0.2 0.05 P(X=x) -0.4| 0.4 0.5 0.5 Adding (-0.4) + (0.4) + (0.5) + (0.5) = 1.| C. -2 -1 1. P(X=x) | 0.16 0.14 | 0.11 | 0.27 | 0.22
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