Determine whether the Existence and Uniqueness of Solution Theorem implies that the given initial value problem has a unique solution. dy y® =x, y(4) = 0 dx O A. The theorem does not imply the existence of a unique solution because is continuous but dy is not continuous in any rectangle containing the point (Type an ordered pair.) OB. The theorem implies the existence of a unique solution because and are both continuous in a rectangle containing the point dy (Type an ordered pair.) The theorem does not imply the existence of a unique solution because is not continuous in any rectangle containing the point C.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Determine whether the Existence and Unigueness of Solution Theorem implies that the given initial value problem has a unique solution,
6 dy
=x°, y(4)= 0
dx
O A. The theorem does not imply the existence of a unique solution because
is continuous but
is not continuous in any rectangle containing the point
(Type an ordered pair.)
OB.
The theorem implies the existence of a unique solution because
are both continuous in a rectangle containing the point
and
dy
(Type an ordered pair.)
The theorem does not imply the existence of a unique solution because
is not continuous in any rectangle containing the point
Transcribed Image Text:Determine whether the Existence and Unigueness of Solution Theorem implies that the given initial value problem has a unique solution, 6 dy =x°, y(4)= 0 dx O A. The theorem does not imply the existence of a unique solution because is continuous but is not continuous in any rectangle containing the point (Type an ordered pair.) OB. The theorem implies the existence of a unique solution because are both continuous in a rectangle containing the point and dy (Type an ordered pair.) The theorem does not imply the existence of a unique solution because is not continuous in any rectangle containing the point
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