Determine whether the given relation is an implicit solution to the given differential equation. Assume that the relationship does define y implicitly as a function of x and use implicit differentiation. 4 siny + xy - x³ = 6, y'= 20x³y' +4(y')³ siny-2 (y')² 5x* - y Applying implicit differentiation to the equation gives which 20x³y' +4(y')³ siny-2(y)² y" = Therefore, 4 sin y + xy - x² = 6 5x equivalent to a solution to the differential equation.

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