Determine whether the series n=0 4 √19 A. The series diverges because lim n-∞ B. Select the correct choice below and, if necessary, fill in the answer box within your choice. D. 11 converges or diverges. If it converges, find its sum. 4 √19 #0 or fails to exist. 4 The series converges because lim √19 n→∞ (Type an exact answer, using radicals as needed.) OC. The series diverges because it is a geometric series with |r| 21. n = 0. The sum of the series is The series converges because it is a geometric series with <1. The sum of the series is (Type an exact answer, using radicals as needed.)
Determine whether the series n=0 4 √19 A. The series diverges because lim n-∞ B. Select the correct choice below and, if necessary, fill in the answer box within your choice. D. 11 converges or diverges. If it converges, find its sum. 4 √19 #0 or fails to exist. 4 The series converges because lim √19 n→∞ (Type an exact answer, using radicals as needed.) OC. The series diverges because it is a geometric series with |r| 21. n = 0. The sum of the series is The series converges because it is a geometric series with <1. The sum of the series is (Type an exact answer, using radicals as needed.)
Chapter9: Sequences, Probability And Counting Theory
Section: Chapter Questions
Problem 25RE: Use the formula for the sum of the first nterms of a geometric series to find S9 , for the series...
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Transcribed Image Text:Determine whether the series >
n=0
4
19
Select the correct choice below and, if necessary, fill in the answer box within your choice.
OA. The series diverges because lim
n→∞
B.
converges or diverges. If it converges, find its sum.
OD.
4
√19
n
#0 or fails to exist.
4
The series converges because lim
√19
n→∞
(Type an exact answer, using radicals as needed.)
OC. The series diverges because it is a geometric series with |r| 21.
The series converges because it is a geometric series with |r|<1. The sum of the series is
(Type an exact answer, using radicals as needed.)
n
= 0. The sum of the series is
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