Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. In(a) – In(b) = In(a - b) for all positive real numbers a and b. O True. Take a = 4 and b = 2. Then In(a) - In(b) = In(4) – In(2) = In = In(2). And In(a - b) = In(4 – 2) = In(2). True. This is one of the Laws of Logarithms. O False. In(a – b) = In(a) - In(b) only for negative real numbers a and b. False. In(a - b) = In(a) – In(b) only for positive real numbers a > b. O False. Take a = 2 and b = 1. Then In(a) – In(b) = In(2) – In(1) = In(2) - 0 = In(2). But In(a - b) = In(2 – 1) = In(1) = 0. O O O

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.1: Real Numbers
Problem 5E
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Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show
why it is false.
In(a) – In(b) = In(a – b) for all positive real numbers a and b.
%3D
4
True. Take a = 4 and b = 2. Then In(a) – In(b) = In(4) – In(2) = In
In(2). And In(a – b) = In(4 – 2) = In(2).
2
True. This is one of the Laws of Logarithms.
False. In(a - b) = In(a) – In(b) only for negative real numbers a and b.
False. In(a - b) = In(a) – In(b) only for positive real numbers a > b.
O False. Take a =
2 and b = 1. Then In(a) – In(b) = In(2) – In(1) = In(2) – 0 = In(2).
But In(a - b) = In(2 - 1) = In(1) = 0.
Transcribed Image Text:Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. In(a) – In(b) = In(a – b) for all positive real numbers a and b. %3D 4 True. Take a = 4 and b = 2. Then In(a) – In(b) = In(4) – In(2) = In In(2). And In(a – b) = In(4 – 2) = In(2). 2 True. This is one of the Laws of Logarithms. False. In(a - b) = In(a) – In(b) only for negative real numbers a and b. False. In(a - b) = In(a) – In(b) only for positive real numbers a > b. O False. Take a = 2 and b = 1. Then In(a) – In(b) = In(2) – In(1) = In(2) – 0 = In(2). But In(a - b) = In(2 - 1) = In(1) = 0.
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