Develop the desktop proof of the following recursive exercise with V = [3,5,2,7] and num = 4 (Logically without the use of programs)
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Develop the desktop proof of the following recursive exercise with V = [3,5,2,7] and num = 4 (Logically without the use of programs)
![int sumavec ( int v[], int num) {
// Pre v es un array de al menos num elementos
int s;
if
(num <= 0 ) S = 0;
else if (num > 0
return s;
// devuelve Σi: 0 ≤i<num : v[i]
s = sumavec(v, num-1) + v[num-1];](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6a3f6b5b-88cd-4b7c-b370-c1248daa8872%2F437d4094-42fd-48c2-93c5-1261f457417e%2Fzym346b_processed.png&w=3840&q=75)
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- An array int[] intArray can be initialized during its definition by A.) It can't be initialized B.) by writing int[] intArray = {1.0f}; C.) by writing int[] intArray = {0,1,2}; D.) by writing int[0-10] intArray = {0,1,2,3,4,5,6,7,8,9};#ifndef lab5ExF_h #define lab5ExF_h typedef struct point { char label[10]; double x ; // x coordinate for point in a Cartesian coordinate system double y; // y coordinate for point in a Cartesian coordinate system double z; // z coordinate for point in a Cartesian coordinate system }Point; void reverse (Point *a, int n); /* REQUIRES: Elements a[0] ... a[n-2], a[n-1] exists. * PROMISES: places the existing Point objects in array a, in reverse order. * The new a[0] value is the old a[n-1] value, the new a[1] is the * old a[n-2], etc. */ int search(const Point* struct_array, const char* target, int n); /* REQUIRES: Elements struct-array[0] ... struct_array[n-2], struct_array[n-1] * exists. target points to string to be searched for. * PROMISES: returns the index of the element in the array that contains an * instance of point with a matching label. Otherwise, if there is * no point in the array that its label matches the target-label, * it should return -1. * If there are more than…A three-dimensional array called watermelon is declared as based on the row-wise manner as below: int watermelon [3][2][2]= {9, 7, 1, 5, 9, 7, 1, 5, 9, 7 ,1, 5}; Rewrite the sequence of watermelon array if it is accessed in column wise manner. Select one: A.9 9 9 7 7 7 1 1 1 5 5 5 B.9 7 1 5 9 9 7 7 1 1 5 5 C.5 1 7 9 5 1 7 9 5 1 7 9 D.9 7 1 5 9 7 1 5 9 7 1 5
- #include <mpi.h> int *Random_Num_Generator(int Num_Elements); int Compute_Product(int *array, int num_elements); int main(int argc, char* argv[]) { int comm_sz, my_rank;int i, Result; int Num_Per_Proc = atoi(argv[1]); // Seed the random number generator to get different results each time srand(time(NULL)); MPI_Init(&argc, &argv); MPI_Comm_rank(MPI_COMM_WORLD, &my_rank); MPI_Comm_size(MPI_COMM_WORLD, &comm_sz); // Generate a random array of elements on process 0int *Random_Nums = NULL; if (my_rank == 0){ Random_Nums = Random_Num_Generator(Num_Per_Proc * comm_sz); printf("The random numbers generated: \n"); for (i = 0; i < Num_Per_Proc * comm_sz; i++) printf("%d; ", Random_Nums[i]); printf("\n");} // Generate a buffer for holding a subset of the entire array int *Sub_Random_Nums = (int *)malloc(sizeof(int) * Num_Per_Proc); // Scatter the random integer numbers from process 0 to all processes MPI_Scatter(Random_Nums,…Send the code in c++ formet. Answer quickly as soon as possible. #include #include #include using namespace std; void printArray(int arr[], int n){ for(int i=0; i> n; int arr[n]; // array elements. for(int i=0; i> arr[i]; } cout << endl << "------------------" << endl; printArray(arr, n); for(int i=0; iMulti Dimensional Arrays in C Program Ask the user for the number of rows and columns of a two-dimensional array and then its integer elements. Then, ask the user for another integer value which represents a boogeyman. A boogeyman is a value that we intend to find from a given array. Find and output the coordinates of the boogeyman by this format: "BOOGEYMAN LOCATED AT ROW {row_number}, COLUMN {column_number}!" Input 1. One line containing an integer for the number of rows 2. One line containing an integer for the number of columns 3. Multiple lines containing at least one integer each line for the elements of the array Sample 1 4 2 3 9 1 2 3 4 2 1 1 9 2 8 3 4. One line containing an integer for the boogeyman's value Output Print the row of the position first and then the column of the position. Note that the row and the column is 0-based (i.e. it starts at 0 and not at 1). It is guaranteed that the boogeyman exists and only once in the 2D array. Enter# of rows: 4 Enter…
- Code for this in C: You have created three arrays:array A of size 100array B of size 50array C of size 200You are to store the first 100 numbers (1,2,3,...,100) into array A, the first 50 positive odd numbers (1,3,5,...,) into array B, and the reciprocal of each position [C(5) = 1/5] into array C. Then, output the contents of each array.Debug C language int element(int arr[], int num) { in i, ele; ele = arr[0]; for (i = 1; i < num; i++) if (arr[i] > ele) ele = arr[i]; return ele; } main() { arr[] = {1, 24, 145, 20, 8, -101, 300}; int n = sizeof(arr)/sizeof(arr[0]); printf("element of array is %d", element(arr[], n)); }using java programming int a[] = {5,10,4,20,1,7}; 1- search for the smallest element in array 2-if you found the smallest element in the array :swap the first element with the smallest element
- #include<stdio.h> #include<iostream>using namespace std; int main() { int arr [7] = {9, 4, 1, 6, 2}; int i, j, k, temp, n=5; for(i=0;i<n-1;i++){ for (j = i+1; j<n; j++){ if (arr[i]>arr[j]){ //swap the elements temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; } } } cout<<"The sorted array is: "; for (k=0; k<n;k++) { cout<<arr[k]<<' '; } } Question: Rewrite the Program using function.Prompt: In Python language, wrte a function that applies the logistic sigmoid function to all elements of a NumPy array. Code: import numpy as np import math import matplotlib.pyplot as plt import pandas as pd def sigmoid(inputArray): modifiedArray = np.zeros(len(inputArray)) #YOUR CODE HERE: return(modifiedArray) def test(): inputs = np.arange(-100, 100, 0.5) outputs = sigmoid(inputs) plt.figure(1) plt.plot(inputs) plt.title('Input') plt.xlabel('Index') plt.ylabel('Value') plt.show() plt.figure(2) plt.plot(outputs,'Black') plt.title('Output') plt.xlabel('Index') plt.ylabel('Value') plt.show() test()Python Coding Exercise: Write a function that takes three parameters: a 2-D array arr, a row location i, a column location j and returns a float representing the fraction of neighbors around arr [i,j] # write your function here:def find_frac(arr,i,j):
