Device Interface P Address FPrefix R1 192.168.0.128 2001 db acad:1 04 192 168 0.17 (28 2001 db acad 10164 Loopbackt 172.10.1.1/24 2001 db acad 171:1/64 Loophark 209.165 200.1 25 2001 db acad 200:164 R2 192.168.0.14 (28 2001 db acad14 64 192.108.0.30 28 2001 db acad 16 2 64 Loopback1 172.18.2.1 24 2001 db8 acad 1721/64 Loopback2 209 165,200. 129/25 2001 dbe acad 210:1 /64

Q: SWi MAC Addresses SW1- 02absc000111 Sw2 - 02abSc0001a1 Sw3 - 02absc001111 SW4 - 02absc00011a SwS -…

A: Spanning tree Spanning tree is created using nodes of the topology.  Steps to create spanning tree…

Q: calculate the subnet mask for the address * .block (200.16.56.90 /29) 255.255.255.254 O non of the…

A: Subnet mask is determined by setting the host id portion of the IP address to all 0 bits and network…

Q: In the MAC address table, a dynamic RAM is utilised to store MAC addresses. Assume the table size is…

A: INTRODUCTION: In most cases, a CPU will access memory (such as RAM) to obtain data for use in its…

Q: Express the following 48-bit binary MAC address in hexadecimal    10101001 - 11111000 -10110111 -…

A: In a MAC address, one hexadecimal digit resembles a group of four contiguous binary bits, called a…

Q: A supernet has the first address ( 192.168.16.0) netid length 22. The Supernet mask is Select one:…

A: The IP address is 192.168.16.0 The netid is 22. This means the number of host bits is 32-22=10

Q: memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and you…

A: The Answer is

Q: In a two-level paging system, each page table entry is 16 bytes and the page size is 16 KB. The root…

A: It is given that level two paging technique and each entry is of size of 16bytes and page size =…

Q: Suppose page faults occur 99% of the time (that is, a page is not in the TLB). What is the average…

A: Answer:

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: The answer is

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: Given: If memory access time is 200 nanoseconds and average page-fault service time is 8…

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: Given: Memory access time = 200 nsecpage-fault service time = 8 msec performance loss of less than…

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: The Answer is

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: Memory access time = 200 nsec page-fault service time = 8 msec Effective Access Time (EAT)EAT = (1 –…

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: INTRO GIVEN DATA   Memory access time = 200 nsecpage-fault service time = 8 msec performance loss of…

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: The answer is

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: INTRODUCTION GIVEN DATA BY YOU  Memory access time = 200 nsec page-fault service time = 8 msec…

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: The answer is

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: In this question, we have,  Memory access time = 200 nanoseconds Page-fault service time = 8…

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: Your answer is given in the 2nd step in handwritten sol.

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: The Answer is

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds,…

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: In the given data, Memory access time (M) = 200 ns Page fault rate (P) = 20% -> 0.2 Average Page…

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: your answer is given below

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: The answer is given in the 2nd step in the form of a handwritten solution.

Q: A system with 64GB memory with a block size of 4 words, and a 256KB direct map cache. The word size…

A: Given: Memory =64 GB that means total bits = log2(64GB)=log2(236)=36 Cache size = 256 KB Block Size=…

Q: Express the following 48-bit binary MAC address in hexadecimal   10101001 – 11111000 –10110111 –…

A: group of 4 bit and write it in range of 0-15 is the rule for writing in hexadecimal .

Q: See the answer Which of the following is a private address space?     170.0.0.0 - 172.31.255.255…

A: Here are some of the address that are only used by Private IP address. =>10.0.0.0 -…

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: The answer is

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: The answer is

Q: If memory access time is 200 nanoseconds and average page-fault service time is 8 milliseconds, and…

A: The answer is as follows:-

Q: q11-  127.0.0.0 – 127.255.255.255  Address range is used for ?   a. Limited broadcast address…

A: The solution for the above given question is given below:

Q: Assume you have a small virtual address space of size 2048 KB, and that the system uses paging, but…

A:

Q: The MAC address table is kept in a dynamic RAM. We will assume an 8000-row table with an access time…

A: Introduction: Dynamic random-access memory (dynamic RAM or DRAM) is type of random-access…

Q: Assuming that no page faults occur, the average time taken to access a virtual address is…

A: Hi there, Please find your solution below, I hope you would find my solution useful and helpful.…

Q: For each of the following decimal virtual address : 32768, 60000. Compute the virtual page number…

A: The solution for the above given question is given below:

Q: nsider a paging system with the page table stored in associative registers. emory reference takes…

A: paging system with the page table stored in associative registers. If a memory reference takes 200…

Q: In the Media Access Control (MAC) address 00:B0:D0:6A:F2:B5, what does 00:B0:D0 identify?

A: MAC: A media access management address (MAC address) may be a distinctive symbol appointed to…

Q: Display the ARP cache. a. Open a command window on your PC (Runà cmd) and type arp. b. Examine the…

A: What command would be used to display all entries in the ARP cache? _____-a_________   What command…

Q: Assume you have a small virtual address space of size 2048 KB, and that the system uses paging, but…

A: Solution: The answer to the above questions are: a) 32 bits. b) 19 bits. c) 13 bits. d) 220 page…

Q: Given a 32-bit virtual address space and a 24-bit physical address, determine the number of bits in…

A: Given: Given a 32-bit virtual address space and a 24-bit physical address,determine the number of…

Q: Given a 32-bit virtual address space and a 24-bit physical address, determine the number of bits in…

A: please check further steps for answer :

Q: Given a 32-bit virtual address space and a 24-bit physical address, determine the number of bits in…

A: Given: Given a 32-bit virtual address space and a 24-bit physical address, determine the number of…

Q: Given a 32-bit virtual address space and a 24-bit physical address, determine the number of bits in…

A: The answer is

Q: Explain the difference between Mb of memory versus communication interface speed.

A: bit:- It is the fundamental unit of information that we use in our computing and also in…

Q: Q3) A computer has a single cache (off-chip) with a 2 ns hit time and a 98% hit rate. Main memory…

A: The cache memory access time is less than the access time of main memory by a factor of 5 to 10. The…

Q: 2. A system that uses a two-level page table has 212-byte pages and 32 -bit virtual addresses. The…

A: Given: -

Q: Given a 16 bit virtual address space and a 10 bit low-order offset how many bytes is each page.

A:

Q: According to the following table if the destination address is 11001000 00010111 00011100 10101010…

A: By doing prefix matching of the given destination address with the address ranges given in the…

Q: Q3: If page in logical address space consists of 32 words. And the size of that address is 12 bits,…

A:

Q: We are given a one-level paging system, where 90% of the times there is a TLB Hit. The time required…

A: Introduction :Given ,One level paging system,TLB hit rate = 90%TLB access time = 5nsMain memory…