Devise a set of ten numbers so that nine of them are “above average,” that is, nine of the numbers are larger than the mean? I found 8,8,8,8,8,8,8,8,8,1 and it works. I need help with the below part. Is it possible to have all of them “above average”? Explain a scenario for how this could happen, and explain a scenario when this is impossible
Devise a set of ten numbers so that nine of them are “above average,” that is, nine of the numbers are larger than the mean? I found 8,8,8,8,8,8,8,8,8,1 and it works. I need help with the below part. Is it possible to have all of them “above average”? Explain a scenario for how this could happen, and explain a scenario when this is impossible
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.1: Measures Of Center
Problem 23PFA
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Devise a set of ten numbers so that nine of them are “above average,” that is, nine of
the numbers are larger than the mean? I found 8,8,8,8,8,8,8,8,8,1 and it works.
I need help with the below part.
Is it possible to have all of them “above average”? Explain a scenario for how this could happen,
and explain a scenario when this is impossible
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