[D/HD] A different PDE has a full general solution is of the form which of the following is a possible solution consistent with the initial conditions ○ u(x, t) = sin(6 × x) × (cos(√7×6× t) +5 sin(√7×6× t)) ○ u(x, t) = sin(6 × πx) × e-7×36x²t + sin(15 × xx) × e-7×225x²t ○ u(x, t) = sin(6 × xx) × €+7×36x²t + sin(15 × πx) × e+7×225x²t u(x, t)=sin(n xx) x e-7n²²t u(x, t0) = sin(6x)+sin(15x) ○ u(x, t) = sin(6 × πx) × e-7×36n²t ○ u(x, t) = sin(15 × xx) × e-7×225²t

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.1PS
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[D/HD] A different PDE has a full general solution is of the form
which of the following is a possible solution consistent with the initial conditions
○ u(x, t) = sin(6 × x) × (cos(√7×6× t) +5 sin(√7×6× t))
○ u(x, t) = sin(6 × πx) × e-7×36x²t + sin(15 × xx) × e-7×225x²t
○ u(x, t) = sin(6 × xx) × €+7×36x²t + sin(15 × πx) × e+7×225x²t
u(x, t)=sin(n xx) x e-7n²²t
u(x, t0) = sin(6x)+sin(15x)
○ u(x, t) = sin(6 × πx) × e-7×36n²t
○ u(x, t) = sin(15 × xx) × e-7×225²t
Transcribed Image Text:[D/HD] A different PDE has a full general solution is of the form which of the following is a possible solution consistent with the initial conditions ○ u(x, t) = sin(6 × x) × (cos(√7×6× t) +5 sin(√7×6× t)) ○ u(x, t) = sin(6 × πx) × e-7×36x²t + sin(15 × xx) × e-7×225x²t ○ u(x, t) = sin(6 × xx) × €+7×36x²t + sin(15 × πx) × e+7×225x²t u(x, t)=sin(n xx) x e-7n²²t u(x, t0) = sin(6x)+sin(15x) ○ u(x, t) = sin(6 × πx) × e-7×36n²t ○ u(x, t) = sin(15 × xx) × e-7×225²t
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