Differentiate: 1 y tan-x

Q: Differentiate = x* sin x tan x. Answer: y

A: Given y=x4 sin x tan x

Q: y = sec(0) tan(8)

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Q: 8.Differentiate and simplify: y = tan(VT). %3D

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Q: Differentiate. y =  2x 7 − tan(x

A: Given  y = 2x7-tan x Apply quotient rule ddxuv = vdudx-udvdxv2

Q: y = 2 tan x

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Q: Differentiate  Sin(msin-1 x)

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Q: Differentiate y=9x2sin(x)tan(x)

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Q: Y 15 12 9,

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Q: Differentiate y = tan (x – V1+x²). y' =

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Q: Write ∫ tan3 x dx in terms of ∫ tan x dx. Then find ∫ tan3 x dx.

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Q: sec I dr = %3D tan I

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Q: Differentiate.   y =  x tan -1(4x)

A: We have to differentiate, y=xtan-14x Here, given integral is in product form so according to product…

Q: Differentiate. V = 3 - sec(x) tan(x)

A: The given function y is in the quotient form. Apply the quotient rule formula

Q: Differentiate. y = sec(0) tan(0) y' =

A: Given,            y=secθ tanθ

Q: Use Substitution method: y' tan x sin2y= sin^2 x+cos^2 y

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Q: Differentiate y = sin (x-y)

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Q: Integrate: - da 9x2+16 O In (3x + v9x2 +16) + C O In (3x + V9x2 +16) +C ㅇ tan ' (뚜) + C 0 tan1 (부) +…

A: Given ∫dx9x2+16

Q: () Differentiate y = tan ex

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Q: Differentiate y = sec x tan x. y =

A: We have to find the derivative of sec(x)tan(x) Please see the explanation below

Q: .S (sec y)*(tan y)*dy

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Q: find tan 2 ¢.

A: Given that,sinθ = 45In a triangle having angle θ as one of its angle,sinθ = Perpendicular…

Q: Differentiate. 1 - sec x y = - tan x y' =

A: We have to differentiate the function   We have the given function as    y=1-sec xtan x

Q: Differentiate. y = 7x2 sin x tan x y' =

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Q: 2. a. arctan(-1) b. tanV3 C. tan-

A: a)tan-1(-1)=-π4b)tan-1(3)=π3

Q: Differentiate xy^2+tan(y^3)=10y

A: Consider the given expression:

Q: 5x3 b. y = %3D x3-sin x

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Q: Differentiate.  y =(1 -sec x) / tan x

A: We have to differentiate the function: y=1-sec xtan x Simplifying the above expression using…

Q: Evaluate / tan*(x) sec*(x) dæ.

A: I=∫tan3(x)sec2(x)dxsubstitute  tanx=udiffrentiatesex2xdx=du

Q: y = 2 - tan x

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Q: Find y'. tan(x + y) = x + y

A: Solution ) tan ( x + y ) = (x + y ) Differentiate with respect to x d/dx tan ( x + y ) = d/dx ( x +…

Q: Differentiate y = x^5 sin x tan x  Answer: y' =

A: Given, y=x5sinx tanx

Q: Differentiate. 3 - sec x y = - tan x y' =

A: Given function: y=3-secxtanx Differentiate the above function w.r.t "x" y'x=ddx3-secxtanx

Q: Differentiate. sin x y = ex – tan x

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Q: Differentiate sin√(x/x+8).

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Q: Differentiate: y = 8 sin(16x*)

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Q: Differentiate y = sec a tan . y' -

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Q: 8x y = 3 - tan(x)

A: Quotient rule of differentiation:

Q: Differentiate y = sin[sin(sin x)] %3D

A: We can differentiate y as below

Q: Differentiate y = tan(x – /1+ x²). y' =

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Q: Differentiate * tan 13 y =

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Q: Differentiate  F(x,y) = tan-1(y/x)

A: given function is  f(x,y)=tan-1(yx)

Q: Differentiate y = tan (ex)

A: y=tan(ex)

Q: Differentiate y = tan(2x).

A: The given function is y=tan(2x)

Q: Evaluate: ) ²dx secx- tanx

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Q: Differentiate the following x 2 tan(y) + y 10 sec(x) = 2x

A: Given that

Q: Describe some similarities and differences between y = cosx and y = secx.

A: Explanation of the answer is as follows