Differentiate the function. Then find an equation of the tangent line at the indicated point on the graph of the function. y = f(x) = 4+√√9-x, (x,y) = (0,7) The derivative of the function y = f(x) = 4 + √√9-x is What is the equation of the tangent line at (0,7)? A. O C. y-7==(x-0) 1 y-7= - = (x-0 0) O B. y-7=6(x - 0) O D. y-7-6(x-0)
Differentiate the function. Then find an equation of the tangent line at the indicated point on the graph of the function. y = f(x) = 4+√√9-x, (x,y) = (0,7) The derivative of the function y = f(x) = 4 + √√9-x is What is the equation of the tangent line at (0,7)? A. O C. y-7==(x-0) 1 y-7= - = (x-0 0) O B. y-7=6(x - 0) O D. y-7-6(x-0)
Chapter3: Functions
Section3.2: Domain And Range
Problem 61SE: The cost in dollars of making x items is given by the function Cx)=10x+500. a. The fixed cost is...
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Transcribed Image Text:Differentiate the function. Then find an equation of the tangent line at the indicated point on the graph of the function.
y = f(x) = 4+√9-x, (x,y) = (0,7)
The derivative of the function y = f(x) = 4+√9-x is
What is the equation of the tangent line at (0,7)?
O A.
O C.
1
y-7=(x-0)
y-7= =
1
6(x-0)
B. y-7=6(x-0)
O D. y-7-6(x-0)
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