Differentiate with respect to x,             y = (2x + 1)(3x + 2)

Q: Find the linearization of-ƒ(x, y) = x2 - xy + 1- 2 y2 + 3?

A: Here we have,  f(x,y) = x2-xy+1-12y2+3 at (3,2)

Q: Solve for y zu 1. In y = 4x - 2x +3 %3D

A: Here, lny=4x2-2x+3

Q: Differentiate with respect to x: * 1 y = (1– x³) 2

A: Follow the procedure given below.

Q: calculate d2y/dx2 when y=.4x-.3

A: Given function is y=4x-3. Power rule of differentiation states that: ddxxn=nxn-1 Differentiating the…

Q: Find the equation bounded by x = 9yeY and x = 3y2, y = 3 and y = 9 %3D %3D Write your answer in two…

A: solution is given below

Q: a. y = x* – 3x² + 2 at a point (1,0)

A: Since you have asked multiple question, we will solve the first question for you as per our guide…

Q: Y Is the midpolnt of XZ.If XZ 8x-4 and YZ = 3x +1, find x.

A: Given Y is the mid-point of line segment XZ XZ = 8x-4 YZ = 3x+1   to solve the given question use…

Q: Differentiate y = sec (x^2 + 2) *

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Q: f (x, y) = x+ 5y 2 +y = 25,

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Q: 1. y=x+5 y= 6

A: A system of linear equations is a set of one or more linear equations. Each linear equation…

Q: on of y" – 2y' + 2y =

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Q: If x < 0 and y > 0, determine the sign of the realnumber. x/y

A: It is given that, x < 0 and y > 0

Q: Use method of variation of parameters. y" +2y-8y = 2e-2x - e-x.

A:

Q: If x < 0 and y > 0, determine the sign of the realnumber. xy2

A: Given that, x < 0 that is x is negative. y > 0 that is y is positive.

Q: Find the linearization of y = 3xe²x-10 at x = 5. %3D

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Q: х-2 y = at [-1,1] x²+1

A: The given problem is to find interpolating polynomial for the given function and interval using…

Q: If y = (x+1)/(2x - root x' then y' will be?

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Q: Differentiate. ' a) y = 2cos(x²)

A: Hi, at a time we can answer only one question and the exact one was not specified. So, I have…

Q: 2) Find of y = क सम्माय 2) r*+1)(2x+3)

A: Simplify the given expression and take log on both sides.…

Q: (3x + y5)dy – ydx = 0 %3D -

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Q: y = v1- x+ x2 ||

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Q: y = In /2x

A: The function is given by y = ln2x

Q: dx V3-2x-x2

A: Explanation of the answer is as follows

Q: Let_y=x² +5x³-4x+1 then dy- ||

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Q: Find the point of inflection of the curve x^3 – 3x^2 –x + 7.

A: For inflection point, second derivative is zero

Q: Differentiate. F(y) = + 9y3) %3D

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Q: 3 (x²-2y+xz) dydzdx = 0. -2 1

A: see 2nd step

Q: Verify that 0t ду дх дх ду 2. 3 y 3 f (x, у) %3D 2х*у — х"у — ху

A:

Q: Find of z = 2x° 5xy" + x¯ y dy2 -10ху + 3x? у? = -10y + 6xy²

A: To find ∂2z∂y2 of z = 2x3-5xy2+x2y3

Q: 1. y+ /x + y = 2x at ( 2, 2)

A: Follow the procedure given below.

Q: Suz z², Y > x², y + 2x – 3 < 0

A: The given system of the inequalities is: y≥x2,y+2x-3&lt;0   The equation y=x2 represents the…

Q: 1. y 2x + 4x at point (-2,0)

A:

Q: Find y' if y = 2vx (3x - 2) at x = 4. %3D

A: We need to find y' at x=4

Q: 4. Perpendicular to x - 3y = 2 and passes thru (-3,5)

A: given that a line is perpendicular to the line x-3y=2 and passes through the point (-3,5). we need…

Q: Find y' for x°y* + 2x + 2y = 128 at the point (2, – 2). At (2, – 2), y' = Preview -

A: The given equation is: x3y4+2x+2y=128...(1) To find y' at the point (2,-2).

Q: Find y' for 4x + 5y* – 1 = 132 at the point (2, – 1). | At (2, – 1), y' = Preview %3D

A: Given: 4x5+5y4-132 To find: y'  at  (2,-1)

Q: y = Vz3 -4z-2 %3D

A: Given: y = z3 - 4z - 23   To find the derivatives.

Q: Differentiate y = x'arctan 2x 2x A. 1+4x2 - 2x arctan 2x 2x3 В. + 2x arctan 2x 1+4x2 C. 1+4x2 + 2x…

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Q: Differentiate with respect to t 100 = x2 + y2

A: give equation ;- 100=X2+Y2 when we differentiate above equation with respect to t , we get

Q: find x: sec² 2x = 4

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Q: - eliminU1 stem of equato y=2t 「し 3x-) 3D3 X+ 2y =3

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Q: Find fxy(-5, 0), if f(x, y) = 3x3y2 - 3x4 + 5xy3.

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Q: Compute Δy/ Δx for the interval [2,4] where y = 5x−7.

A: ∆y∆x for function y=f(x) for the interval [a,b] = f(b)-f(a)b-a

Q: Find The derivatve of this fanction y= (x-1)(x-4) (2-2)(x-3)

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Q: If x &lt; 0 and y &gt; 0, determine the sign of the realnumber. xy

A: Let x&lt;0 and y&gt;0

Q: Find 1- y dy y+2 using the substitutionu +5= √√y+2.

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Q: Differentiate : a. y= (2Inx^2) b. y= In (xInx)

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Q: а a²-x² ху(х + у)dydx 0. x,

A: Integration of function expression with respect to variable x or y gives the area under function…