Differentiate x' +4 y = 5х — 3

Q: How come it is 20y and not 20y^2/2 after integrating?

A:

Q: Find the differential dy. y = 6x7 + 3x2

A: Given:y=6x7+3x2

Q: and dr= %3D Solve for the differential of y When y=sinxx x

A:

Q: [2 ln (x)+1] dy in yty cosy %3D dx

A:

Q: dy ion =1+y de uden Teul

A:

Q: Find dy/dx by implicit differentiation. 52) x3 + y3 = 5

A: Given implicit function : x3+y3=5

Q: Calculate the differential of the function y=x5−7x3+5x at the point x=2 when dx=0,2.

A:

Q: dx S COsxtanx

A: Here we will solve the given integration,

Q: Determine the anti-derivative of Y = 2e3x +5 and use the fact that y(0) = 7 to %3D dx determine c,…

A: We first separate the variables and then integrate  c= integrating constant Formula used:

Q: Find the first and second derivatives. 6x5 y = - 7x+4 ex dy %3D dx dx II

A:

Q: Find dx at x--3 if y-5x-2 and Do NOT Round.

A:

Q: Find dy/dx by implicit differentiation. ex/y = 2x − y

A: Given:

Q: Find dy/dx by implicit differentiation. 8.r2y+ 5yr = -9 y 5y + 16x 2x 4x + 5y dy/dx = %3D

A: Recall: d(u.v)dx=udvdx+ dudxv d(xn)dx=n xn-1 d(c)dx=0 ; where 'c' is any constant.

Q: Find dy/dx by implicit differentiation. 6/(x^6) + 6/(y^6) = 14

A: We have to find dy/dx by implicit differentiation.

Q: 2e*/y dy dx 2.

A:

Q: Find Ans= dy dx for y = 3x + ex x² - 5

A: Using formula of d/dx(U/V)

Q: 4. FIND d²y BY IMPLICIT DIFFERENTIATION: x² + y² = 81 %3D dx2

A: Given: x2+y2=81

Q: If y = 4x³ + 2x² + 11, find the approximate value of y when x = 2.01, using differentials.

A:

Q: Differentiate. y =x° In x- dy II

A:

Q: find the soution of' the differential eq. System X= 3X+44 9=X+3y %3D

A: Given differential equations are                                     dxdt=3x+4y,dydt=x+3y…

Q: Find the differential of the function y=xxe2x at the point x=1.

A:

Q: Solve for the differential of y when y=sinxx• x=-. and dx= 3 4 2

A: i am going to solve the given problem by using some simple calculus to get the required result.

Q: Find dy/dx by implicit differentiation. 2(x^2+y^2)^2 = 25(x^2-y^2)

A:

Q: The integrating factor of Y + 3y cscx= cotx is?

A: Consider the given differential equation, y'+3ycscx=cotx This is the first order linear differential…

Q: dy/dx of y=sec^-1 (5x)

A:

Q: TO Show Jv - x-V そーレ V+ dx

A: Jvx = ∑m=0∞ -1mx22m+vm! m+v!

Q: Find dy/dx by implicit differentiation. (7x + y = 5 + x²y² (-2xy² – 2/7x + y ²2y – 8 y' =

A:

Q: Find dy/dx by implicit differentiation. x4y1/4 = 18x+6y6

A: This question is based on the differentiation of Implicit function.

Q: (continue solution of de) (2ysinxcosx - y + 2y²e*Y" )dx = (x - sin²x - 4xye*y" )dy

A: Using method of exact differential equation.

Q: 3z cos(z)dz

A:

Q: 3. у?dx— x(2х + Зу)dy %3D -

A:

Q: dy 3. y = [(x + 1)(x – 1)]³, dx dy 4. y = (t + 4)(t – 2)(t – 1), dt 12/07/2021 15:

A:

Q: Find dy/dx by implicit differentiation. 19) x3 + y3 = 5 20) 2xy-y2=1

A:

Q: -5 1 -dx Jo 2x+4 1 dt 2 V6-t 1 ii) S,

A:

Q: dy Exc:" of y = tanh (x5 – 5x)² --

A: Solution:Given         y=tanh4(x5-5x)2  To find dydxFormula:ddx(xn)=nxn-1ddx(tanh x)=sech2x

Q: Solve dy : dx y In y

A: We solve the given problem by substitution

Q: If Va + Vy = 6 and y(25) = 1, find y' (25) by implicit differentiation. %3D %3D

A:

Q: Find the differential dy when x = 3 and dx = 0.2 %3D

A: When you get function of function form to differentiate, we use the chain rule. y = f(g(x)) dy/dx =…

Q: Integrate both sides dy = -dx

A: the given integral equation is                             ∫1y2dy=∫1xdx

Q: Give the integrating factor for 3((y^4)+1)dx+4x(y^3)dy=0. (in terms of x)

A:

Q: ion dy 3t2 dt 2y + 2t3y' tion: ||

A:

Q: To use differentials to approximate V8. You would use x = and dx

A:

Q: Differentiate implicitly to find dy dx x²-10xy + y²-4x+y-4 = 0

A:

Q: Differentiate. y=de* +6 dx

A: Given y=ex+6

Q: 3. (2х - у - 4) dx - (х-3)dy -0 when x %3 1, y 3D 4.

A: We try to identify and group terms and integrate.

Q: Calculate cln 2 I = Ver – 1 dx thanks to the change of variable u Ver – 1. U = -

A:

Q: aur + 2xyury + y*uyy = 0

A:

Q: Differentiate the function. 1 y3= (2x +3) dy dx

A: