Direction: Fill in the blanks with the next step in solving the solutions of the differential equation of 3 (¹ + 1) dx + 4xy³ dy = 0 . Write your answer in the reply box below. M = 3 (¹+1) N = 4xy³ &M A) partial derivatives of M with respect to y set as a constant dy = B) partial derivatives of N with respect to a set y as a constant difference between the partials derivative Integrating factor N = F) partial derivatives of M with respect to y set a as a constant partial derivatives of N with respect to a set y as a constant = 1) integral of M Ndy ="). integral of N General Solution of 3 (y² + 1) dx + 4xy³ dy = 0 K)_ = SM SN) = C) by 6 = D) New Representation of: M = E) Test Again for exactness: 8M = G) dy = H) - J Mdx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Non Exact Differential Equation 

 

Direction : Fill in the blanks with the next step in solving the solutions of the differential equation of 3 (y² + 1) dx + 4xy³ dy = 0 . Write your answer in the reply box below.
M = 3 3 (¹+1)
N = 4xy³
&M
= A)
partial derivatives of M with respect to y set as a constant
dy
= B)
partial derivatives of N with respect to a set y as a constant
SN) = C)
difference between the partials derivative
= D)
Integrating factor
New Representation of:
M = E)
N =
F)
Test Again for exactness :
¡M
partial derivatives of M with respect to y set x as a constant
dy
= H)
partial derivatives of N with respect to a set y as a constant
f Mdx = 1)
integral of M
[ Ndy =))
integral of N
General Solution of 3 (y² + 1) dx + 4xy³ dy = 0 K)_
EN
da
SM
dy
Transcribed Image Text:Direction : Fill in the blanks with the next step in solving the solutions of the differential equation of 3 (y² + 1) dx + 4xy³ dy = 0 . Write your answer in the reply box below. M = 3 3 (¹+1) N = 4xy³ &M = A) partial derivatives of M with respect to y set as a constant dy = B) partial derivatives of N with respect to a set y as a constant SN) = C) difference between the partials derivative = D) Integrating factor New Representation of: M = E) N = F) Test Again for exactness : ¡M partial derivatives of M with respect to y set x as a constant dy = H) partial derivatives of N with respect to a set y as a constant f Mdx = 1) integral of M [ Ndy =)) integral of N General Solution of 3 (y² + 1) dx + 4xy³ dy = 0 K)_ EN da SM dy
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