Discuss the effect of changing field size on PDD. Explain why this effect occurs
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Discuss the effect of changing field size on PDD. Explain why this effect occurs.
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- please solve 8 and 9at a microscopic level, something similar to a circular electrical current is occurring. Using what you know about atoms, suggest a reason there may be something like "circular current" at a microscopic level in a bar magnet.Find the acceleration in Pm/s2 (1P = 1015, for theelectron in problem #48.a. using a chargedensity of o = 3.54 uC/m2.
- A 4.3-MeV (kinetic energy) proton enters a 0.21-T field, in a plane perpendicular to the field. What is the radius of its path?The top of the atmosphere is at about 400 kV with respect to the surface of the earth, corresponding to an electric field that decreases with altitude. Near the surface of the earth, the field is about 100 Vm-1 Why then do we not get an electric shock as we step out of our house into the open? (Assume the house to be a steel cage so there is no field inside!)Q1: The vector potential of magnetic field in free space is given as:(A= 40 r´ ăz ) Wb/m. i) Find (A, H, B, and J) at (r-1, 0Please type instead of hand writtingIf neededBoltzmann Constant=1.38×10-23 J/K = 8.62×10-5eV/KUnit charge= 1.602 ×10-5 CPlanck’s constant= 6.626×10−34 J.sec=4.136×10−15 eV.secUse the following constants if necessary. Coulomb constant, k=8.987×109N•M2/C2. Vacuum permitivity, €0=8.854x10-12F/m. Magnetic Permeability of vacuum, µo=12.566370614356×10-7H/m. Magnitude of the Charge of one electron, e=-1.60217662x10-19C. Mass of one electron, me=9.10938356x10-31kg. Unless specified otherwise, each symbol carries their usual meaning. For example, µC means microcoulomb. The figure (Fig. 1) shows a long cylindrical capacitor consists of a solid conducting core with radius ri=3mm and outer hollow conducting tube with an inner radius of r2=33mm. The length of the capacitor is L=27cm. Figure 2 is the cross sectional view of the system. This system of rod and shell is connected to a voltage source of emf E=6.4volts. There is no dielectric material present in the system as of now. Fg-2 A) Calculate the capacitance of this capacitor. B) Say the inner rod is positively charged. Given this, calculate the charge density of the outer surface. And show how the electric field…The magnetic dipole moment of the gadolinium atom is about 6.3 ✕ 10−23 A · m2. (a) Calculate the maximum magnetic dipole moment (in A · m2) of a domain consisting of 1019 gadolinium atoms. (b) What current (in A) would have to flow through a single circular loop of wire of diameter 1.2 cm to produce the magnetic dipole moment you calculated?How you conclude that the all superconductors are diamagnetic but alldiamagnetic materials are not superconductors.Use the following constants if necessary. Coulomb constant, k = 8.987 × 10°N · m²2/c². Vacuum permitivity, eo = 8.854 × 10-12 F/m. Magnetic Permeability of vacuum, Ho = 12.566370614356 × 10 -/H[m. Magnitude of the Charge of one electron, F|m. e = - 1.60217662 × 10-19 C. Mass of one electron, m. = 9.10938356 × 10 - 31 kg. Unless specified otherwise, each symbol carries their usual meaning. For example, µC means micro coulomb. Given that, there is two current carrying wire. One is carrying /, = 8 mA current in the -1j direction and the other wire is carrying 12 = 6 mA current in the 1j direction. The seperation between the two parallel wires is d = 13 cm. If we consider a Length L = 85 m then what is the Magnitude of the Force acting on the wire segment. Use + sign for attractive force and - for repulsive. Force acting on the wire is? Give your answer up to at least three significance digits.SEE MORE QUESTIONS