(Number 12) thanks! Conjugate Pairs Theorem - P(x)= 0 is a polynomial equation with real coefficients and thecomplex number a+bi (b0) is a root, then a-bi is also a root.10.Create a polynomial equation with real coefficients that has 2 and 1-i as roots.Descartes's Rule of Signs - Suppose P(x)=0 is a polynomial equation with real coefficients andwith terms written in descending order.The number of positive real roots of the equation is either equal to the number ofvariations of sign of P(x) or less than that by an even number.The number of negative real roots of the equation is either equal to the number ofvariations of sign of P(-x) or less than that by an even numberDiscuss the possibilities for the roots to :2x - 5x² – 6x+4 = 012.3x*-5x' -x² - 8x+4=0|

We can use Descartes rule of signs to check the nature of possible roots of the given function, P(x)…

Answered: Discuss the possibilities for the roots…

Math

Advanced Math

Discuss the possibilities for the roots to : 2x'-5x - 6x+4 = 0 12. 3x - 5x -x² -8x+4 =0

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter3: Polynomial And Rational Functions

Section3.5: Complex Zeros And The Fundamental Theorem Of Algebra

Problem 74E

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Question

(Number 12) thanks!

Conjugate Pairs Theorem - P(x)= 0 is a polynomial equation with real coefficients and the
complex number a+bi (b0) is a root, then a-bi is also a root.
10.
Create a polynomial equation with real coefficients that has 2 and 1-i as roots.
Descartes's Rule of Signs - Suppose P(x)=0 is a polynomial equation with real coefficients and
with terms written in descending order.
The number of positive real roots of the equation is either equal to the number of
variations of sign of P(x) or less than that by an even number.
The number of negative real roots of the equation is either equal to the number of
variations of sign of P(-x) or less than that by an even number
Discuss the possibilities for the roots to :
2x - 5x² – 6x+4 = 0
12.3x*-5x' -x² - 8x+4=0
|

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