Divide the text in the declared variable above into an array String I animals separated by comma. The division of text must be done using programming not by setting the values into an array. Write a for loop with if condition to solve this or other methods
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- Write a program using arrays that generate 20 random integers between 10 and 90 and then storesit in an array. Your goal is to find: Mean Median ModeFor this question, provide switch menu to user in order to select one of the option fromabove.write a code that will fill the array a int a[4][5]; with numbers typed at the keyboardHow would I transform the following program to allow the user to input an odd number of positive integers in a single line (space-separated). In other words, how would I change the array to allow user input? The program should output the number that occurs the odd number of times. Code to be Modified: #include <iostream> using namespace std; int getNumOccurredOdd(int arr[], int n) { int res = 0; for (int i = 0; i < n; i++) res = res ^ arr[i]; return res; } int main() { int arr[] = {3, 4, 6, 5, 6, 3, 5, 4, 6, 3, 5, 5, 3}; int n = sizeof(arr)/sizeof(arr[0]); cout << getNumOccurredOdd(arr, n) << " is present odd number of times"; }
- Suppose we expect the elements of the array a to be ordered so thata[0] ≤ a [1] ≤ a [2]≤ ...However, to be safe we want our program to test the array and issue a warningin case it turns out that some elements are out of order. The following code issupposed to output such a warning, but it contains a bug. What is the bug?double[] a = new double[10];<Some code to fill the array a goes here.>for (int index = 0; index < a.length; index++)if (a[index] > a[index + 1])System.out.println("Array elements " + index +" and " + (index + 1) + " are out of order.");Can you make the array be randomly genorated instead of already named values, and ask the user to enter the number of numbers that will be genorated in the array. Everything else can stay the same. '''def binary_search(arr, x): low = 0high = len(arr) - 1mid = 0while low <= high: mid = (high + low) // 2if arr[mid] < x: low = mid + 1elif arr[mid] > x: high = mid - 1else: return mid return -1arr = [ 2, 3, 4, 10, 40 ] print("The array is [ 2, 3, 4, 10, 40 ]")x = int(input("Enter which value do you seek to find from the array above? "))while not (x==2 or x==3 or x==4 or x == 10 or x == 40):print("Option isn't in the array.")x = int(input("Please input a valid number to search "))result = binary_search(arr, x) print("Searching for", x) if result != -1: print("Element is present at index", str(result))Extend your random generating program to make sure that the numbers are unique. In another words, if the number has been generated and appear early, it should continue to find the next number until the number is unique. If the count is greater than the range, the program will print out an error message because it is not possible to generate that many unique numbers. Hint: use the array to check whether the number has been generated iN C++
- Write a hangman game that randomly generates a word andprompts the user to guess one letter at a time, as presented in the sample run.Each letter in the word is displayed as an asterisk. When the user makes a correctguess, the actual letter is then displayed. When the user finishes a word, displaythe number of misses and ask the user whether to continue to play with anotherword. Declare an array to store words, as follows:// Add any words you wish in this arrayString[] words = {"write", "that",...}; (Guess) Enter a letter in word ******* > p↵Enter(Guess) Enter a letter in word p****** > r↵Enter(Guess) Enter a letter in word pr**r** > p↵Enterp is already in the word(Guess) Enter a letter in word pr**r** > o↵Enter(Guess) Enter a letter in word pro*r** > g↵Enter(Guess) Enter a letter in word progr** > n↵Entern is not in the word(Guess) Enter a letter in word progr** > m↵Enter(Guess) Enter a letter in word progr*m > a↵EnterThe word is program. You missed 1 timeDo…Can you help me please: have the program know when numbers out of the array boundaries are received and mitigate those problems. The given code intentionally induces numbers out of bounds and the student’s portion must correct for this. As always use a header file and implementation file to do those calculations. Remember not to change the given code below in any way Design and implement the class myArray that solves the array index out of bounds problem and also allows the user to begin the array index starting at any integer, positive or negative. Every object of type myArray is an array of type int. During execution, when accessing an array component, if the index is out of bounds, the program must terminate with an appropriate error message. Consider the following statements:myArray list(5); //Line 1 myArraymyList(2, 13); //Line 2myArray yourList(-5, 9); //Line 3The statement in Line 1 declares list to be an…Please submit your solution to the lab instructor once you have your program working. Your lab instructor will tell you how (s)he would like you to turn it in. Failure to submit will result in a zero. Write a program that asks the user to input two integers a and b. Then create an array that has all integer from a to b. Print out the array. (Don’t forget to consider the situation of a=b, a<b, and a>b.) Example 1: Input two numbers: 6 2 Array is [6, 5, 4, 3, 2] Example 2: Input two numbers: 4 8 Array is [4, 5, 6, 7, 8] Pass the above array as a parameter to a method called average and return the average and print it out in the main method. (Do not use Math library to get the average.) Please attach your screenshot below to each question a and b.
- This is what I have so far I need help with the commenting up the code My c code #include <stdio.h> int largest(int a[], int n); int largest(int a[], int n) { int large=a[0]; for(int i=1;i<n;i++) { if(large<a[i]) { large=a[i]; } } return large; } int main() { int n; int largest_num; int a[50]; printf("enter the size of an array"); scanf("%d",&n); printf("\n Enter the elements in an array:"); for(int i=0;i<n;i++) { scanf("%d",&a[i]); } largest_num=largest(a,n); printf("Largest number in array:%d",largest_num); return 0; } My assembly code largest(int*, int): push rbp mov rbp, rsp mov QWORD PTR [rbp-24], rdi mov DWORD PTR [rbp-28], esi mov rax, QWORD PTR [rbp-24] mov eax, DWORD PTR [rax] mov DWORD PTR [rbp-4], eax mov DWORD PTR [rbp-8], 1…CORAL LANGUAGE PLEASE Write code that loops through the array userVals. Each iteration: If userVals[i] is less than 25, put userVals[i] to output, and then put "." to output. Else, assign userVals[i] with userVals[i] plus 2. integer iinteger array(5) userVals for i = 0; i < userVals.size; i = i + 1 userVals[i] = Get next input // Your solution goes here Put "\nArray values: " to outputfor i = 0; i < userVals.size; i = i + 1 Put userVals[i] to output Put " " to outputWrite a program that creates an integer array of size 10 and fills the array with valuesset by the programmer (not entered by the user). Then, the program will remove all theprime numbers from the original array and store them in a new array. Note that afterthe program finishes execution, the original array should not contain any prime number.
