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Do the following limits exist ? If yes, find their value xy lim (x, y) (0,0) x² + y² xy lim (x, y)-(1,-1) x² + y² lim (x, y)→(0,0) theorem.) ху (Ans: No) x2 lim (x, y)→(0,0) x8 + 7y² (Ans: Yes, and the limit is) (Ans: Yes, and the limit is 0. Hint: Observe (Ans: No). y-x lim (x, y)-(1,-1) 1-y + ln(x) xy = lyl and use Squeeze

Do the following limits exist ? If yes, find their value xy lim (x, y) (0,0) x² + y² xy lim (x, y)-(1,-1) x² + y² lim (x, y)→(0,0) theorem.) ху (Ans: No) x2 lim (x, y)→(0,0) x8 + 7y² (Ans: Yes, and the limit is) (Ans: Yes, and the limit is 0. Hint: Observe (Ans: No). y-x lim (x, y)-(1,-1) 1-y + ln(x) xy = lyl and use Squeeze

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section: Chapter Questions
Problem 12T
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Do the following limits exist ? If yes, find their value ху lim (x, y)→(0,0) x² + y² (Ans: No) ху lim (x, y)→(1,−1) x² + y² lim (x, y)→(0,0) theorem.) (Ans: Yes, and the limit is) ху 1x² + y² (Ans: Yes, and the limit is 0. Hint: Observe x^y lim (x, y)→(0,0) x³ + 7y² y - x lim (x, y)-(1,-1) 1-y + ln(x) (Ans: No). ху + y² < ху √x² = [y] and use Squeeze
Transcribed Image Text:Do the following limits exist ? If yes, find their value ху lim (x, y)→(0,0) x² + y² (Ans: No) ху lim (x, y)→(1,−1) x² + y² lim (x, y)→(0,0) theorem.) (Ans: Yes, and the limit is) ху 1x² + y² (Ans: Yes, and the limit is 0. Hint: Observe x^y lim (x, y)→(0,0) x³ + 7y² y - x lim (x, y)-(1,-1) 1-y + ln(x) (Ans: No). ху + y² < ху √x² = [y] and use Squeeze
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