Do vectors wi = 2+x and w2 = 3 – x, span P1 (R) E Expand

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter1: Vectors
Section1.1: The Geometry And Algebra Of Vectors
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How do I find the basis for these two vectors?

Do vectors wi = 2+ x and w2 = 3 – x, span Pi(R)
E Expand
Transcribed Image Text
Do vectors wi = 2+ x and w2 3- X, Span P1(R)
V Expert Answer
Step 1
Do vectors
w, = 2+1
Si W2 = 3-
Spans RR)
et
a+ba E P. (R)
Step 2
Now
atbn = pwit qwz
at ba= P(2+a)+9(3-2)
(2P4 34) + (P-9)<
atba =
2p+39 =9
P-9=6
Solving bol5
5= 4-26
9= 9-26
=) P = b+q=b+ 8~26
P = a+3b
Then atbr =
+36 (2+a) +i
> atbn= Gt3b w, +
9+36
=) W, Wz Spens PCIR)
Transcribed Image Text:Do vectors wi = 2+ x and w2 = 3 – x, span Pi(R) E Expand Transcribed Image Text Do vectors wi = 2+ x and w2 3- X, Span P1(R) V Expert Answer Step 1 Do vectors w, = 2+1 Si W2 = 3- Spans RR) et a+ba E P. (R) Step 2 Now atbn = pwit qwz at ba= P(2+a)+9(3-2) (2P4 34) + (P-9)< atba = 2p+39 =9 P-9=6 Solving bol5 5= 4-26 9= 9-26 =) P = b+q=b+ 8~26 P = a+3b Then atbr = +36 (2+a) +i > atbn= Gt3b w, + 9+36 =) W, Wz Spens PCIR)
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