does the series E infinity/n=1 2^n/3^n converge or diverge a)the series converges because its is a p-series with p.1 b)the series diverges because it is a p-series with p,=1 c)the series diverges because it is a geometric series with !r!>=1 d)the series converges because it is a geometric series with !r!<1
does the series E infinity/n=1 2^n/3^n converge or diverge a)the series converges because its is a p-series with p.1 b)the series diverges because it is a p-series with p,=1 c)the series diverges because it is a geometric series with !r!>=1 d)the series converges because it is a geometric series with !r!<1
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.3: Geometric Sequences
Problem 49E
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does the series
E infinity/n=1 2^n/3^n converge or diverge
a)the series converges because its is a p-series with p.1
b)the series diverges because it is a p-series with p,=1
c)the series diverges because it is a geometric series with !r!>=1
d)the series converges because it is a geometric series with !r!<1
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