Drafa is a fictional recessive disease corresponding to genotype dd Two parents show no symptoms so they are either DD or Dd. The order does not matter so DD cross Dd is the same as Dd cross DD. How many possible combinations of crossings (Punnett squares) are there? [Select] Let X be the event their first child is a carrier of Drafa (genotype Dd). Let A = DD cross DD and B = DD cross Dd and C = Dd cross Dd P(X|A) [Select ] P(X|B) = [Select] P(XIC)= [Select] If P(A) = 9/10, P(B) = 1/16, P(C) = 3/80, then use the formula P(X) P(XA)P(A) + P(X|B)P(B) + P(X|C)P(C) to calculate P(X) [Select]

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter8: Sequences, Series,and Probability
Section8.6: Counting Principles
Problem 74E: Lottery Powerball is a lottery game that is operated by the Multi-State Lottery Association and is...
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Drafa is a fictional recessive disease corresponding to genotype dd
Two parents show no symptoms so they are either DD or Dd.
The order does not matter so DD cross Dd is the same as Dd cross DD. How many possible
combinations of crossings (Punnett squares) are there? [Select]
Let X be the event their first child is a carrier of Drafa (genotype Dd).
Let A = DD cross DD and B = DD cross Dd and C = Dd cross Dd
P(X|A) = [Select]
P(XB) = [Select]
P(XIC) = [Select]
If P(A) = 9/10, P(B) = 1/16, P(C) = 3/80, then use the formula
P(X) = P(X|A)P(A) + P(X|B)P(B) + P(XIC)P(C)
to calculate P(X)
=
[Select]
Transcribed Image Text:Drafa is a fictional recessive disease corresponding to genotype dd Two parents show no symptoms so they are either DD or Dd. The order does not matter so DD cross Dd is the same as Dd cross DD. How many possible combinations of crossings (Punnett squares) are there? [Select] Let X be the event their first child is a carrier of Drafa (genotype Dd). Let A = DD cross DD and B = DD cross Dd and C = Dd cross Dd P(X|A) = [Select] P(XB) = [Select] P(XIC) = [Select] If P(A) = 9/10, P(B) = 1/16, P(C) = 3/80, then use the formula P(X) = P(X|A)P(A) + P(X|B)P(B) + P(XIC)P(C) to calculate P(X) = [Select]
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