Drag a function or an interval into each box to correctly complete the statement. When the domain of the non-imnveritie function f (x) = (x+1) -3 [-1, 00). ,the inverse of the function is and the domain of the inverse function is f1 (x) = Vx- 3+1 [-1, 0) [3, 0) f (x) = Va+3 - 1[-3, 0)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.5: Graphs Of Functions
Problem 54E
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How does a domain restriction placed on a non-invertible function affect its inverse?
Drag a function or an interval into each box to correctly complete the statement.
= (x+1) - 3[-1, 0).
When the domain of the non-invertible function
, the inverse of
is
the function is
and the domain of the inverse function is
f1 (x) = Va - 3+1 [-1, 0) [3, o0)
f1 (x) = Va+3 – 1[-3, 00)
Transcribed Image Text:How does a domain restriction placed on a non-invertible function affect its inverse? Drag a function or an interval into each box to correctly complete the statement. = (x+1) - 3[-1, 0). When the domain of the non-invertible function , the inverse of is the function is and the domain of the inverse function is f1 (x) = Va - 3+1 [-1, 0) [3, o0) f1 (x) = Va+3 – 1[-3, 00)
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