Draw the graph of the inequality: y> 4x +3 You can refer to Participation Activities 11 and 12 in the Reading and Participation section Graphing Linear Inequalities. Those two activities can give you practice in drawing graphs of linear inequalities in Mobius. Part a: Find two points on the associated line. Often it's smart to start with the values x = 0 and x = 1. The point (0, Number ) is on the line y = 4x + 3. The point (1, Number ) is on the line y = 4x + 3.

Intermediate Algebra
19th Edition
ISBN:9780998625720
Author:Lynn Marecek
Publisher:Lynn Marecek
Chapter3: Graphs And Functions
Section3.4: Graph Linear Inequalities In Two Variables
Problem 279E: The doctor tells Laura she needs to exercise enough to burn 500 calories each day. She prefers to...
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Draw the graph of the inequality:
y> 4x +3
You can refer to Participation Activities 11 and 12 in the Reading and Participation section Graphing
Linear Inequalities. Those two activities can give you practice in drawing graphs of linear inequalities in
Mobius.
Part a: Find two points on the associated line. Often it's smart to start with the values x = 0 and x = 1.
The point (0, Number ) is on the line y = 4x + 3.
The point (1, Number
) is on the line y = 4x +3.
Part b: Find a point that satisfies the strict inequality y > 4x + 3.
The point (0,
B) satisfies y > 4x + 3.
Part c: To sketch this inequality, first sketch the boundary line using the
area icon
line icon
icon and then use the
to choose either the region above the line or below the line. Finally use the solid-dashed
to convert the boundary line from a solid line to a dashed line if appropriate.
Transcribed Image Text:Draw the graph of the inequality: y> 4x +3 You can refer to Participation Activities 11 and 12 in the Reading and Participation section Graphing Linear Inequalities. Those two activities can give you practice in drawing graphs of linear inequalities in Mobius. Part a: Find two points on the associated line. Often it's smart to start with the values x = 0 and x = 1. The point (0, Number ) is on the line y = 4x + 3. The point (1, Number ) is on the line y = 4x +3. Part b: Find a point that satisfies the strict inequality y > 4x + 3. The point (0, B) satisfies y > 4x + 3. Part c: To sketch this inequality, first sketch the boundary line using the area icon line icon icon and then use the to choose either the region above the line or below the line. Finally use the solid-dashed to convert the boundary line from a solid line to a dashed line if appropriate.
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