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- Under balanced operating conditions, consider the three-phase complex power delivered by the three-phase source to the three-phase load. Match the following expressions, those on the left to those on the right. (i) Realpower, P3 (a) (3VLLIL)VA (ii) Reactive power, Q3 (b) (3VLLILsin)var (iii) Total apparent power, S3 (c) (3VLLILcos)W (iv) Complex power, S3 (d) P3+jQ3 Note that VLL is the rms line-to-line voltage, IL is the rms line current, and is the power-factor angle.A balanced -connected impedance load with (12+j9) per phase is supplied by a balanced three-phase 60-Hz,208-V source, (a) Calculate the line current, the total real and reactive power absorbed by the load, the load power factor, and the apparent load power, (b) Sketch a phasor diagram showing the line currents, the line-to-line source voltages, and the -load currents. Use Vab as the reference.Let a series RLC network be connected to a source voltage V, drawing a current I. (a) In terms of the load impedance Z=ZZ, find expressions for P and Q, from complex power considerations. (b) Express p(t) in terms of P and Q, by choosing i(t)=2Icost. (c) For the case of Z=R+jL+1/jC, interpret the result of part (b) in terms of P,QL, and Qc. In particular, if 2LC=1, when the inductive and capacitive reactances cancel, comment on what happens.
- A single-phase 100-kVA,2400/240-volt,60-Hz distribution transformer is used as a step-down transformer. The load, which is connected to the 240-volt secondary winding, absorbs 60 kVA at 0.8 power factor lagging and is at 230 volts. Assuming an ideal transformer, calculate the following: (a) primary voltage, (b) load impedance, (c) load impedance referred to the primary, and (d) the real and reactive power supplied to the primary winding.The instantaneous voltage across a circuit element is v(t)=400sin(t+30)volts, and the instantaneous current entering the positive terminal of the circuit element is i(t)=100cos(t+10)A. For both the current and voltage, determine (a) the maximum value, (b) the rms value, and (C) the phasor expression, using cos(t) as the reference.A two-winding transformer rated at 100 kVA, is connected as an autotransformer to provide 10kV from a 15kV supply. Calculate the new rated kVA output. consider the power transformer mode and calculate the related currents Where, Vp = 10000VIp = S/(√3Vp) Is = S/(√3Vs) When find the new currents and voltages proceed to find the primary and secondary powers of the autotransformer. And conclude the rating of the autotransformer.
- The impedance ZL in the circuit shown in Figure is adjusted for maximumaverage power transfer to itself.(a) What should be the value of ZL?(b) What is the maximum average power delivered to ZL?(c) What percentage of the average power delivered to the linear transformer is delivered to ZL?3) A 120 KVA three -phase transformer (three -phase power), 13200/480 V (line a line) in delta-strella connection has a resistance of 1.3% and a reactance of 8.2% per unit. a) Calculate the phase impedance of the transformer referred to the bass side voltage. b) Calculate the phase impedance of the transformer referred to the high side voltage. c) Calculate the efficiency of the transformer into nominal conditions and with F.P. 0.8 in delay. Three -phase loss in the nucleus is 1500 W.In the above figure, a single line model of a three-phase power system is given. Base power 50MVA, base voltage 13.8kV according to its value, a) Per-unit values of power system circuit elements according to the given base power and base voltage values. calculate. b) The perunit you calculate by drawing the equivalent impedance circuit for one phase of the power system given in the figure. show on the values.
- If the turn ratio of a step-down transformer is 10:1 and the series impedance (referred to the primary) of j50 ohm. If the no-load primary voltage is 230 kV (line-to-line), the secondary side is serving a Y-connected balance load of 1.5+ j0.25 ohms, the reactive power (per phase) absorbed by the load would be?A transformer has a ratio of 4:1. The high voltage side is connected to a 240 Vrms source. The low voltage side (secondary) is connected to an impedance ZL = 20 + j10 Ω.a. What is the value of the load impedance when referred to the primary?b. (in A rms) What is the current out of the source?Which termination would result to a phase change of 180 degrees at the load if Zo = 100 ohm? a. 50 ohm b. short circuit c. 75 ohm d. all of these What is the purpose of impedance matching? a. maximum return loss b. maximum SWR c. maximum load power d. maximum reflection A short piece of transmission line that may be open or shorted and used for impedance matching purposes. a. converter b. decoder c. stub d. transformer