dx Evaluate 121 324x2 dx 121-324x2 (Use C as an arbitrary constant.)

Q: Evaluate.   ∫7x^8+5x^3−2 dx = _________ (Use C as the arbitrary​ constant.)

A:

Q: f(3x² cot 2x³ csc 2x³) dx O-csc 2x³ + C CSC O csc 2x³ + C Ocsc 2x³ + C CSC O-csc 2x³ + C

A: We can solve as follows

Q: foo 0 dx e²x

A:

Q: fxe dx. B. (i) Evaluate

A:

Q: e dx

A: Definite integration

Q: csc5x cot5x dx A csc 5x B -csc5x 3 -csc5x 3 D csc5x E None

A:

Q: I + 5 dx x3 – x Evaluate

A:

Q: tan-lx dx 3+ 3x2 1. Evaluate

A:

Q: x4 +1 x³+9x -dx

A:

Q: dx Evaluate – 12x - 12x dx 12x - 12x

A:

Q: 2x² +9 x4 + 10x² + 25 dx

A: given

Q: cosec2x dx 2 Evaluate

A: Solve the following

Q: 3x3 4x2 + 3x dx 12 x2 +1

A: we have to evaluate the following integral

Q: dx Evaluate 25 121x2 dx 861890 25 121x2 (Use C as an arbitrary constant.)

A: The given integral is,

Q: a dx Evaluate (4a² +9x*)

A: This question is based on Indefinite Integration.

Q: 2tan-(x) dx = (b- in4 (+ In2 (- in4 (e)None In2

A:

Q: 3х -1 dx /3x²-2x

A:

Q: 6x –dx x² +1 Evaluate

A:

Q: dx Evaluate 256 289x2 dx 256-289x (Use C as an arbitrary constant.)

A: Substitute for x as follows.

Q: 4x2 -6 dx. x - 4x2 Evaluate

A: Consider the given integration as ∫4x2-6x3-4x2dx

Q: x2 + 15x - 10 dx = x3 - 4x2 - 5x dx X-5 x+1 Determine the value for A, B, and C.

A:

Q: Vx2 –9 a x2 dx

A:

Q: Reciprocal Substitution – x³ )/3 dx

A:

Q: e -dx x2 a)

A: There are multiple questions. As per company policy Kindly ask other question separately.

Q: ​Evaluate:   ∫24x^5 dx = ____ ​(Use C as the arbitrary​ constant.)

A:

Q: 2х-3 dx. (b) Evaluate 3x²-15x+1

A: Since you have asked multiple question, as per our guidelines we are supposed to answer only one…

Q: 6. 22x+x dx 5. f 22x

A:

Q: termine the follow a. S=dx x6

A:

Q: e3x - 00 1+e3x –3 dx =

A: Given,            ∫-∞-3e3x1+e3xdx

Q: csc* x dx cot6 x Evaluate

A:

Q: (2x²– 4x + 4) dx Evaluate: -1

A: This is a basic definite integration problem

Q: 24 dx (144x²+1) Evaluate S- 2

A: Here we have to find the integral.

Q: 2x +5 Evaluate dx Vx² -2x+10N

A:

Q: 3. [ (sec²(a) — csc²(a) + π) da

A: We will use formulas of integration to solve it

Q: 4. (*x3-8| - (x3+8) dx

A:

Q: x(х-2) dx (x-1)3 Evaluate

A:

Q: |a3 – 8| – (x³ + 8) dx x3

A:

Q: csc5x cot5x dx 5csc5x (A csc5x B csc 1 -csc5x 3 В 1 -csc5x 3 D csc5x None

A:

Q: (x³-4) dx x3+2x2+2x

A: Here we have to integrate the given Integral.

Q: 3x2 + 5 dx. x2 – 3x +2 Evaluate

A: Integrate∫3x2+5x2−3x+2dx

Q: 5x+3_ dx Evaluate : x2 +2X

A: The integration can be solved by decomposing the integral . This can be done by rewriting the…

Q: x' - 5 dx. (ii) Evaluate x' + 4x

A:

Q: x²+4 dx (x-5)(x2+9)

A: ∫x2+4x-5x2+9dx Here use partial fraction and find  integration…

Q: .5 x (x – 3)? dx = - (x - 3)3 dx Fill out the blank:

A: Given: ∫25xx-32 dx=....... -∫2513x-33 dx To Find: The fill in the blank

Q: 2x4+5x2 – 3x +7 dx. Evaluate x2 +3

A: To findI=∫2x4+5x2-3x+7x2+3dx

Q: Arctan'ax dx= b Arctan"3x +C , what is b? 1+9x²

A:

Q: 00 x3 dx (x²+1)² it

A:

Q: x2 - 9 dx x3

A:

Q: e2¤ csc²(e2" ) cot²(e2") dr. CSC“ -d.x e2 + cot e2¤

A: Given: Let I=∫e2x csc2e2x cot2e2xe2+cote2x dx To Find: To evaluate the given integral.