dx J-16x 398. dx x|/4x* -16 402.

Q: Q2. Integrate dx

A:

Q: [ (x²ex - 12/²7/1₁) dx x + 1,

A:

Q: 9. f²-2x(3x - 1) dx

A:

Q: T (3 sec² x + 4 csc² x) dx 3

A: The given integral,        ∫π3π43sec2x+4csc2xdx

Q: 은 J4-√x dx

A: This question can be solved using integration by substitution.

Q: [xVtan x² sec* x² dx -

A: Given,         ∫xtanx2sec4x2dx

Q: dy Find dx = (3x - 5)(x² + 2x).

A:

Q: (4cscxcotx + 2 sec² x)dx

A:

Q: Q2\ find when y = dx x²-1

A: y=xx2-1⇒y=x12x2-1⇒y=x1212x2-1⇒y=x14x2-1

Q: I/3 1 dx Ja16 \1+ tanx. R/6

A: SOLUTION:Given let   I = ∫π6π311+tan xdx= ∫π6π3cos xcos x+sin xdx=12∫π6π32cos xcos x+sin…

Q: x3 dx J4- x4

A: ∫x3dx4-9x4Multiply & divide by -36 =-136∫-36x3dx4-9x4since, ∫f'(x)f(x)dx= 2f(x)

Q: sech - x dx , 0 < x < 1

A:

Q: 1 dx x² V5 -

A:

Q: = vt – 2. a²y y = t2 – 3' dx²

A: The solution are next step

Q: 1 dx 5 (V² -9) x² – 9

A:

Q: dy Y- (3-2x') (3x+5x) (7-2х); dx

A: Derivative

Q: Integrate dx/(x-5)^2

A: answer = -1x-5explanation is given in below step

Q: 3 y = 2x' + 5x from the point (-2,-26) to the point (4,148), you'd have to compute f(x)dx a

A: Given function is                                                        y=2x3+5x we have to find…

Q: 4- x²+4 dx ht. 23

A: To evaluate∫x3x2+4dx We can find the integral by substitution method.

Q: 3x dx V1-x

A: Integral is given

Q: sinh e Incot3x h- dx St 1+9x²

A:

Q: Differentiate the function. -2 y= [(3x2 +4x +5) (x – 4) < dy dx II

A: We can use the chain rule of derivative in order to solve the given problem.

Q: dx/dt = square root5 - ex,

A: As per the company rule, we are supposed to solve one problem from a set of multiple problems.…

Q: sech x dx , 0 < x < 1

A:

Q: Find dy/dx.  s = t4 - csc t + 14

A: Consider  s=t4−csct+14

Q: dx S x-Vx2+1

A: Given that, ∫1x2x2+1dx

Q: 3 sinx 19. dx V1-x²

A:

Q: 5) y = tanx secx 6) Y = b x+1

A:

Q: 3- f xvx2 +1 dx

A: Integration

Q: 41Stañdx= Q22x+1 X'+2X+1

A: (1) Given integral is ∫tan−1xdx It can be written as ∫tan−1x⋅1dx Use integration formula…

Q: 4. Evaluate -dx. V16 – x2 -

A: Given integral:

Q: + 2r -1 dx (x2 – x – 2)

A: Disclaimer: "Since you have asked multiple questions, we will solve the first question for you. If…

Q: 2. dx ***S 1 - x4

A: Integral

Q: /is [sec2(x) – csc²(x)]dx Evaluate:

A:

Q: 9. S." §, x*V9-x dx 16 dx Vx-2 10.

A: We need to evaluate the given definite integrals, to sove we will use the substitution method.

Q: dy - ¿°cax-4) .y(5) - D dx

A:

Q: 13. dx x5-3

A:

Q: V4- V4-x dx 11.

A: Solution of question as follows

Q: Evaluate and simplify. L dx 1 V1-2x-x²

A:

Q: dy _ ху+3х— у-3 dx ху - 2х + 4у -8

A:

Q: Q.a) S V9-4x2 dx sec?x secx tanx b) [sec²x dx sec2x+secx+3

A: We Trigonometry substitution method to solve these integration

Q: 3x + 1 dx 28. V4 – x2 -

A: Formula used : ∫dx1-x2=arcsin(x)+c

Q: Evaluate:

A: Given integral is We know that

Q: 3. dx V3-x

A:

Q: sec²(/x) dx 38.

A: According to the guideline we should have been able to solve only one question at a time #38

Q: 2-3x dx V2x -x+5

A: Given: ∫2-3x2x2-x+5dx

Q: dy Flnd - of x³+y³=6xy dx

A:

Q: to use absolut 5n dx (x- 1)(x2 + 4)

A:

Q: 3. dx 6X dx VT-x2 1-x² Et2

A: