dy - (2xy + y ²) 2+ dx B) Write the equation for the tangent line where x = 2 and y = 1. (2,1) 16 FL dy dx (2,1) H -(2(2)(1) + 1² 22 +2.2.1 Mach THCK y = - =//(x-2) + 1 (4+1) 4+4 11 C) Find the coordinates of the point (x, y) where the curve has a horizontal tangent line. slope 0 = (аху ту + y²) x² + 2xy 2x C 0 = - 2xy - Y 0=Y (-2x-y) 2

Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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C only.

find the coordinates of the point (x,y)with a horizontal tangent lune

product
Consider the curve x²y + y²x = 6
A) Find
dy
dx
in terms of x and y
product
2
² + 2y = 4 x + y ₂² (₁) = 0
dy dy
Free Response
|
2xy + y²x² + 2y y'x+ ¹ y ² = 0
dy
dx (2,1)
2xy
+-
2xy + y ² +_dy (x² + 2xy) = 0
2
dx
dy:- (2xy + y ²)
dx
2+ 2xy
B) Write the equation for the tangent line where x = 2 and y = 1. (2,1)
- (2(2)(1) + 1²)
2²+2.2.1
16 Flamingo MathTM (Jean Adams)
5
8.
y=-
y = - 12/2² (x-2) + 1
4+
4+4
X
x² + 2xy
- 동
C) Find the coordinates of the point (x, y) where the curve has a horizontal tangent line.
0 = = (2xy + y ²)
slope
per.1
0 = - 2xy-y²
0= y(-2x - y)
Transcribed Image Text:product Consider the curve x²y + y²x = 6 A) Find dy dx in terms of x and y product 2 ² + 2y = 4 x + y ₂² (₁) = 0 dy dy Free Response | 2xy + y²x² + 2y y'x+ ¹ y ² = 0 dy dx (2,1) 2xy +- 2xy + y ² +_dy (x² + 2xy) = 0 2 dx dy:- (2xy + y ²) dx 2+ 2xy B) Write the equation for the tangent line where x = 2 and y = 1. (2,1) - (2(2)(1) + 1²) 2²+2.2.1 16 Flamingo MathTM (Jean Adams) 5 8. y=- y = - 12/2² (x-2) + 1 4+ 4+4 X x² + 2xy - 동 C) Find the coordinates of the point (x, y) where the curve has a horizontal tangent line. 0 = = (2xy + y ²) slope per.1 0 = - 2xy-y² 0= y(-2x - y)
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