dy 2y tan x+ y´ tan² x, if y = 1 at x = 0 dx 4.

Q: dy dx Sin (x+y=1)

A:

Q: dy Find for y = tan-(3z) de Ans=

A: A detailed solution is given below.

Q: dy Find dx x/3 S sin (P)at y = dy dx

A: Leibniz rule:

Q: dy Q2 Find dx of x = tan(y)?

A:

Q: Find I for y = tan(x) ||

A:

Q: dy given that In(x + y2)-tan-1 31) Find = 0. dx

A: Given: lnx2+y2-tan-1yx=0 To Find: dydx=?

Q: dy/dx= tan^2 (x) / sec^2 (y), y=pie/4 when x=0

A: given,                 dydx=tan2xsec2y and           y   = π4 when x =0

Q: a) 3dy = sin(x)(y² – y)da dy + (x + 5)y= 5xe 2 dx

A:

Q: Find dy/dx if y= tan-1(x/(1-x))

A:

Q: Find dy Sin (x-qy) xe %3D 24 dx

A:

Q: dy Determine the general solution of = 1+ 3y tanx. dx

A:

Q: dy is let y = (sin æ)*an 7 then dx

A: Given

Q: slove the DE cos x dx/dy +ysinx =sinx cosx

A: r(x) = y'(cos x)  +y(sinx) =sinx cosx   The complementary equation Put r(x) = 0  is (cos x)y' + (sin…

Q: Find dy/dx for the fo d) x' + x.tan y = y -1

A: There are multiple question, As per our company policy ask other question separately. d.

Q: (cos y+ ycosx)dx + (sin x –xsin y)dy = o

A:

Q: dy given that In(x + y2)-tan- = 0. Find dx

A:

Q: D. (e' sin y+ tan y) dx+ (e cos y +x sec y) dy 0

A:

Q: 1+ x 1 then find dy when – 1<<1. dx If y = tan

A: We will find out the required value.

Q: dy 1) = dx cos(x – y) + sin(y+x)

A:

Q: dy Q-2-Find : y³ In tanx – 2* +÷In(3x + 5) = 0 dx

A:

Q: dy at x = 0 where y dx arctan(0.1arcsin(x)) + x² + 3x. Find

A:

Q: dy for y = 3 sin-(x²). J. Find dx

A:

Q: dy at the given point. dx Calculate sin² (–5y) = x + y, - %3D 4

A: Given equation sin2(-5y)=x+y and point 2-π4,π4 The objective is to calculatedydx at the point.

Q: VSDE of tan xdx + y * cos^2 ((x) * dy) = 0

A: The objective is to solve sinxcos xdx+ycos2ydy=0 The formula for integration is ∫xndx=xn+1n+1+c

Q: dy Q3) If y = In[sec 0 + tan 0) find- dx

A: To find dy/d(theta)

Q: Find dy dx 21) tan y = eX + In 4x eX + 4 A) - sin² y хeх + 4 B) - xcot y

A: Given;  tany=ex+ln(4x).

Q: 2. a“y dx2 dy + 42+ 3y = sin(x) + 2 cos(x) dx

A:

Q: Given tanh-1(xy) = xy, find d²y dx2

A:

Q: Find dy/dx by implic differatiation. c)sin(xy)=cos(x+y)

A: to find dydx of  sin(xy)=cos(x+y)

Q: dy/dx of y=(tan^-1 (x))^3x

A:

Q: dy Find for y=7x sin x+14x cos x-14 sln x. dy

A:

Q: find dy/dx. y = 4/cos x + 1/tan x

A:

Q: 2/ Find dy To y=sin h'(tanx) 2-y (X+1)}

A:

Q: dy sin(4x) Find for y dz V1 - x4 dy de

A: The given expression is y=sin(4x)1-x4. Find the derivative of the expression. The quotient rule of…

Q: dy Find dx y = = 5x° sin x coS X

A:

Q: dy x(2 In x +1) 6) dx sin y + ycos y

A:

Q: dy for y=In (x² +1}+ (sin x +5)*. Find dx

A:

Q: dy Find for: dx tanx a) y = xaT b) y = (Inx + x)'

A: Since you have asked multiple question, we will solve the first question for you as per our guide…

Q: Q3: dy\dx off(x)= tan x cot x is

A: Given,    f(x) = tan(x) cot(x)         = 1   As we know, inverse of tan(x) is cot(x).

Q: Find dy/dx d) -1 x' + x.tan y= y

A:

Q: dy Given y= 5e3X + sin x, -is dx

A: differentiate y with respect to x  with the help of differentiation properties we will solve the…

Q: ) (2ху — tanу)dx + (x* — хsec*y)dy 3D 0

A: Given: (2xy-tany)dx+(x2-xsec2y)dy=0

Q: 5. dy/dx + (y/x ) = ( y/x )? 6. x² dy/dx -y² = 0 du u YCot x dx = tan? x dx ; y = 2 when x = %3D 4.

A: Solve above differential equations.

Q: Dy/dx of tan y=ln (cos2 y/ 1 + sin y)   - x

A:

Q: dy x(2lnx+1) dx sin y + y cos y

A:

Q: Find dy/dx if a. y = (sin-1 x)2 b. y = sin-1 (1/ x) .

A: a.The given function is y = (sin–1 x)2.

Q: (x + tan y) dy = sin 2y dx

A: Given: x+tanydy=sin2ydx To find the solution of the given differential equation. If the linear…

Q: FIND dy/dx 1- tan x y= (1+X)

A: