dy 5x+4 given that y = dx I. Use 4-step rule to find 2х-3 II. Differentiate the following: 4x2-9 1. у%3D5-4х - Зx4 6. y = 2x+3 2x 2. f(x) = 7. y = (b2/3 – x2/3); b is a constant %3D 1+x 3. H(z) = (1 – 5z²)4/3 3 1-x2 8. у%3D 1+x2 9. V(x) = V5 + Vx уз 4. g(w) = (3w - 2)*(5w – 4)2 10. QG) = + 3 5. G(u) = u (u + 1)²(u + 2) 3 y3 In each of the following, find the value of dy for the given value of x. dx III. 1. у%3 3 = -- - 2x3 ;x = -1 2. y = xVx + ; x = 4 - 4 3 5 x2 +x-1 3. у %3D ; x = 0 4.y = (3 – x?)(x – 1)3 ; x = 2 x2-1 5. у %3D 1-x2 ;x = 2 IV. Find of the following. dx Jx = vI-t 1. ly = V1+t 3t X = 1+t3 2. 3t2 y 1+t t +-1
dy 5x+4 given that y = dx I. Use 4-step rule to find 2х-3 II. Differentiate the following: 4x2-9 1. у%3D5-4х - Зx4 6. y = 2x+3 2x 2. f(x) = 7. y = (b2/3 – x2/3); b is a constant %3D 1+x 3. H(z) = (1 – 5z²)4/3 3 1-x2 8. у%3D 1+x2 9. V(x) = V5 + Vx уз 4. g(w) = (3w - 2)*(5w – 4)2 10. QG) = + 3 5. G(u) = u (u + 1)²(u + 2) 3 y3 In each of the following, find the value of dy for the given value of x. dx III. 1. у%3 3 = -- - 2x3 ;x = -1 2. y = xVx + ; x = 4 - 4 3 5 x2 +x-1 3. у %3D ; x = 0 4.y = (3 – x?)(x – 1)3 ; x = 2 x2-1 5. у %3D 1-x2 ;x = 2 IV. Find of the following. dx Jx = vI-t 1. ly = V1+t 3t X = 1+t3 2. 3t2 y 1+t t +-1
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:dy
5x+4
given that y =
dx
I.
Use 4-step rule to find
2х-3
П.
Differentiate the following:
1. у%3D 5 — 4х -Зх4
4x2-9
6. у %3D
2x+3
2x
2. f(x) =
7. y = (b2/3 – x2/3); b is a constant
1+x
3
1-x2
3. Н(2) %3D (1 — 5z?)4/3
8. у%3
1+x2
9. V(x) = V5+ Vx
4. g(w) = (3w - 2)*(5w – 4)²
5. G(u) = u³(u + 1)2(u + 2)
%3D
y3
10. Q(y) =
3
3
y3
In each of the following, find the value of
dy
for the given value of x.
dx
III.
x?
2x3
+
3
3
2
1. y =:
;x = -1
2. y = xVx +
V* i x = 4
4
5
x2 +x-1
3. у%3D
;x = 0
4.y = (3 – x?)(x – 1)3 ; x = 2
x2-1
5. у%3D
;x = 2
1-x2
IV.
Find Y of the following.
dx
Jx = VI-t
ly = VI+t
%3D
1.
%3D
3t
X =
1+t3
2.
3t2
y
1+t3
t + -1
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