dy dx de dx = || 0(x) M(x) EI dM dx dv dx = : V(x) = = w(x) Where: x = distance along the beam y = deflection 0 = slope E = modulus of elasticity of the beam I = moment of inertia of the cross-section of the beam M(x) = bending moment at x V = shear force at x w(x) = distributed load at x

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Using C language.
In the mechanics of deformable bodies, the following relationships can be used to analyze
uniform beams subject to distributed loads:
dy
dx
0 (x)
M(x)
de
dx EI
dM
dx
dV
dx
=
= V(x)
=
w(x)
Where:
x = distance along the beam
y = deflection
0 = slope
E = modulus of elasticity of the beam
I = moment of inertia of the cross-section of
the beam
M(x) = bending moment at x
V = shear force at x
w(x) = distributed load at x
You measure the following deflections at seven points along the length of a uniform beam:
1.125
1.5
1.875
x [m] 0.375 0.75
-0.2571 -0.9484 -1.9689 -3.2262 -4.6414
y [cm]
Employ 4th-order approximation for derivatives to compute the bending moment (in kNm),
the shear force (in kN), and the distributed load (in kN/m) at the middle or fourth point.
Use the following parameter values in your computation: E = 200 GPa, and I
= 200 GPa, and I = 0.0003 m4.
NOTES:
1. Ask the user for the modulus of elasticity.
2. Ask the user for the moment of inertia.
2.25
2.625
-6.1503 -7.7051
3. Ask the user for the distance, h, between points along the length of the beam.
4. Ask the user for the deflection at seven adjacent points along the length of the
building component from left to right.
5. Print the internal bending moment, shear force, and distributed load at the middle or
fourth inputted point.
*Note that your program should work for any set of E, I, h, and seven deflection values.
Input E (GPa): 200
Input I (m^4): 0.0003
Input h (m): 0.375
Input deflection of 7 consecutive points (cm):
Point 1: -0.2571
Point 2: -0.9484
Point 3: -1.9689
Point 4: -3.2262
Point 5: -4.6414
Point 6: -6.1503
Point 7: -7.7051
The moment at the middle point is -668.48 kN-m.
The shear at the middle point is 818.20 kN.
The load at the middle point is -443.48 kN/m.
sample input and output
Transcribed Image Text:Using C language. In the mechanics of deformable bodies, the following relationships can be used to analyze uniform beams subject to distributed loads: dy dx 0 (x) M(x) de dx EI dM dx dV dx = = V(x) = w(x) Where: x = distance along the beam y = deflection 0 = slope E = modulus of elasticity of the beam I = moment of inertia of the cross-section of the beam M(x) = bending moment at x V = shear force at x w(x) = distributed load at x You measure the following deflections at seven points along the length of a uniform beam: 1.125 1.5 1.875 x [m] 0.375 0.75 -0.2571 -0.9484 -1.9689 -3.2262 -4.6414 y [cm] Employ 4th-order approximation for derivatives to compute the bending moment (in kNm), the shear force (in kN), and the distributed load (in kN/m) at the middle or fourth point. Use the following parameter values in your computation: E = 200 GPa, and I = 200 GPa, and I = 0.0003 m4. NOTES: 1. Ask the user for the modulus of elasticity. 2. Ask the user for the moment of inertia. 2.25 2.625 -6.1503 -7.7051 3. Ask the user for the distance, h, between points along the length of the beam. 4. Ask the user for the deflection at seven adjacent points along the length of the building component from left to right. 5. Print the internal bending moment, shear force, and distributed load at the middle or fourth inputted point. *Note that your program should work for any set of E, I, h, and seven deflection values. Input E (GPa): 200 Input I (m^4): 0.0003 Input h (m): 0.375 Input deflection of 7 consecutive points (cm): Point 1: -0.2571 Point 2: -0.9484 Point 3: -1.9689 Point 4: -3.2262 Point 5: -4.6414 Point 6: -6.1503 Point 7: -7.7051 The moment at the middle point is -668.48 kN-m. The shear at the middle point is 818.20 kN. The load at the middle point is -443.48 kN/m. sample input and output
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