dy = dx Use separation of variables to solve the differential equation condition y(1) = -2. (Hint: After you isolate 1+2 on one side of the equation, break it into the sum of two x fractions.) You get the solution: O c. y² = ln x| + x − 3 - 1+ with initial xy O A. y² = ln |x| + x + 1 B. This one can be separated, but it's impossible to solve using techniques of antidifferentiation. D. /y² = 1/(x + 1)² O E. y² = (x + 1)² + 3

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