dy if 4y°t + t°y = 5 and dx dt 1 Find dx cos t dy dx

Q: Find dy/dx. x = t sin(t),    y = t2 + 6t

A: given ,        x = t sint        y = t2 + 6t

Q: Find dy/dæ in terms of t if x =t – t°, y = 2+ 4t dy/dx =

A: The differentiation of parametric form of functions can be done by using the formula,

Q: dy dt 1 if 7y't + t°y = 5 and dx Find dx Cos t dy

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Q: dy 5 if y = 2x² + 5 and dt dx Find at x 4. dt dx dt

A: Solving the problem by finding the value.

Q: find dy/dx. y = cos x/x + x/cos x

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Q: Find dy/dæ in terms of æ and y if æ°y – x – 2y – 1 = 0. dy dx

A: We have to find dydx in terms of x and y if x3y-x-2y-1=0.

Q: dy Find if y sec-(e"). dx dy dx ||

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Q: dy dt 1 if 4y°t + t°y = 5 and dx Find dx cos t dy %3D dx

A: Given; 4y3t + t3y = 5 and dt/dx = 1/cost.

Q: If x =t-1+5 and y 6+t-2 then dy at t = dx is

A: topic - derivatives answer is 4

Q: Find dy/dx and d2y/dx2 of x= t + 1/t, y= t + 1

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Q: dy dt when x = 2. Let xy = 3 and Find dx dt 5.

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Q: Find dy if y = (1 – æ*) * dx

A: The function is given by y =1-x314 To evaluate : The expression

Q: dy 3x2 + 2 and dt dx Find 3 if y = – 2. at x - dt dx dt

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Q: find dy>dt.                                                        y = cos4 (sec2 3t)

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Q: dy dt 1 if 5y°t + t°y = 3 and dx Find dx cos t dy dx

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Q: Find dy if x=t+6f and y= dx 2 5 at t=1 +

A: We have to find dy/dx

Q: Consider the following. y = tx2 + t8x Find dy dx dy dx dy Find dt dy dt

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Q: Find dy/dx in terms of a and y if aty – x- 2y- 2 = 0. dy %3D dx

A: It is implicit  derivative.

Q: dy dt 1 if 2y°t + t°y = 3 and dx Find dx cos t dy dx

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Q: dy Find dx S cos (1)dt y = dy dx II

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Q: dy dt 1 Find if 4y°t + t°y = 2 and dx dx cos t dy dx

A: To find dydx here we need to use both chain rule and product rule of differentiation.

Q: Find dy if y=X+Sin xy Find dy if 2x. 3y= 8 2- dx 2

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Q: Given x = 2 cos t + 8 and y= 4 sint dx (i) dt dy (ii) dt dy (iii) dx ||

A: Givenx=2cost+8y=4sin2t

Q: -1 if y = rsin V1-x „Find dy dx

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Q: dy = 3. dt dx at x = 4 if y = - 2x² + 5 and dt Find dx dt

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Q: dy Find dx S cos (P) at y = COS dy dx II

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Q: determine dy/dx if xy = ecsch(x)+πcos(0)

A: Given, xy = ecsch(x)+πcos(0)

Q: dy Find dx if cos(x)cos(y) = sin(x)sin(y) + 3x + 3y – 2. O 1 O -2

A: Given:       cosxcosy=sinxsiny+3x+3y-2       cosxcosy-sinxsiny=3x+3y-2 We know that…

Q: dy Find for y = cos (8at + 1). dt dy dt

A: We have to find out dy/dt for given y

Q: If x= 2t +t+1 and y=8t+3t+2 then dy at t=1 is dx

A: We have to find value of dy/dx at x=1.

Q: (а) dy/dat = sin 2x. (b) dx + e dy = 0. (с) zdy/dx — у. (d) cosec y dx + sec2 x dy = 0. dP (e) dt Р-…

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Q: find dy/dx. y = x2 cos x

A: Here given function as Use the product rule of derivative

Q: -If x= cot- VE, y = ;, find dy dx'dx2 at t = 2.

A: We will use the formula (f(g(x))' = f'(g(x))g'(x)uv' = vu'-uv'v2 Given x = cot-1ty = 1t+1 Then dxdt…

Q: Q5.a) Find if sec?y = x? + t² dt Jsiny dx dy pcotx b) Find if tan²y = x² + VE² +1 dt dx

A: Solution:a) Given :sec2y=x2+∫sinxcosyt2 dt

Q: find dy/dx y Cos()= 2x+Y 2

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Q: dy 2) Find implicitly: dx (a) xy+3x2 =y? (b) exy – Iny =x? %3D

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Q: Find 4 at the point t = 5. dy dx c(t) = (t^, t³ – 3) dy dx (at t = 5) = ||

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Q: dw (C): If w = tan x and x = 4t³ + t ; Find ? dt dy

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Q: dz az B. Find əx and ay 3. x eY+ cos xy36xz+5x²

A: partial derivative

Q: dy Find dx 1/4 y = S sin (*)dt dy dx II

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Q: dy if x = In(csc y +c dx Calculate

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Q: 3. (ey + 1) cosx dx + eysinx dy = 0 [Answer: (ey + 1) sinx = c]

A: As per rule of bartleby we can solve only one question at a time and we can solve only three subpart…

Q: dy Find dx T/4 | cos ()dt y% = CoS X, dy %3D dx

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Q: If x = 1 + t3 and y = 5t – t² then dy at t = 1 is : dx 2 3 None 3

A: Find the derivative of y with respect to x using chain rule

Q: Find dy dx dy d.x = if 3y³t + t³y = 4 and d.t dx = 1 cos t

A: Given

Q: x=24 sin t + 6 and y=24 cos t+39 Find: 1)dx/dt 2)dy/dt 3)dy/dx

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Q: dy if y = cos(ln x). dx Find dy dx

A: Given :   y = cos ( ln x)  now we find dy/dx

Q: 4 cos x Let y = [, (2t + 1) (t + 8t)'/3 dt. Find dy/dx.

A: We will find out the required derivative for given function.

Q: Find dy/dx √(1+cos^2y) =xy

A: Given  (1+cos2y) = xywe find dydx

Q: dy 1 cos t + 1 dt 2 || ||

A: