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dz = S = 3³ 73 where is the square with vertices -1-i, 1-i¸‚\+i‚-¹ + i Let I = since 2=0 S if by residue theorem r dz here Z3 here & where how, we know that 4(4) (2-2₁)h+1 -Iti - 1-i f(²)= f(²)= lies in a square = 2πi Res f(₂) 2-0 S 2²3 Z3 r f(²)= r 73 Res f(a) = 20 23 (2) is analytic function with 4 (20) #0 4 (2) dz 23 1+0 - &"(0) 2! دره - 2) then Res f(²)= 2=20 :: using this value in O = 2πci (0) = = = O 2! 0 / ;. $(4) = 1 4 (20) n! (:. 4²(²) = 4" (²₁) = 0) we get.

dz = S = 3³ 73 where is the square with vertices -1-i, 1-i¸‚\+i‚-¹ + i Let I = since 2=0 S if by residue theorem r dz here Z3 here & where how, we know that 4(4) (2-2₁)h+1 -Iti - 1-i f(²)= f(²)= lies in a square = 2πi Res f(₂) 2-0 S 2²3 Z3 r f(²)= r 73 Res f(a) = 20 23 (2) is analytic function with 4 (20) #0 4 (2) dz 23 1+0 - &"(0) 2! دره - 2) then Res f(²)= 2=20 :: using this value in O = 2πci (0) = = = O 2! 0 / ;. $(4) = 1 4 (20) n! (:. 4²(²) = 4" (²₁) = 0) we get.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section: Chapter Questions
Problem 12RE
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Let I = where is the square with vertices -1-i, 1-i, ¹+í¸‚-¹ + i if now, S r since Z=0 :: by residue theorem S here & dz here 73 dz 73 where -iti -1-i f(²)= f(²)= we know that 4 (4) (2-20)h+1 lies in a square dz Z3 r = 2πi Res f(2) 2-0 1 f (²) = 273 73 Res f(²)= 2= 0 140 dz N i-i (2) is analytic function with $ (20) #0 23 then Res f(2)= 2=20 &"(0) 2! using this value in D, we get. επί (0) = ο (Z) = دره - 2) 3 = Ⓡ O 2! ;. $(4) = 1 <=0 4 (20) n! (:. 4² (²) = 4" (2₁) = 0)
Transcribed Image Text:Let I = where is the square with vertices -1-i, 1-i, ¹+í¸‚-¹ + i if now, S r since Z=0 :: by residue theorem S here & dz here 73 dz 73 where -iti -1-i f(²)= f(²)= we know that 4 (4) (2-20)h+1 lies in a square dz Z3 r = 2πi Res f(2) 2-0 1 f (²) = 273 73 Res f(²)= 2= 0 140 dz N i-i (2) is analytic function with $ (20) #0 23 then Res f(2)= 2=20 &"(0) 2! using this value in D, we get. επί (0) = ο (Z) = دره - 2) 3 = Ⓡ O 2! ;. $(4) = 1 <=0 4 (20) n! (:. 4² (²) = 4" (2₁) = 0)
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